You need to construct fence around an area of 3136 ft2. What are the dimensions of the rectangular pen that minimize the amount of material needed
1 answer:
Answer:
Step-by-step explanation:
The the area of the rectangular pen be A = LW
L is the length
W is the width
Given
A = 3136ft²
3136 = LW..........1
Given the perimeter P = 2L+2W....... 2
From 1; L = 3136/W
Substitute into 2
P = 2(3136/W)+2W
P = 6272/W + 2W
In order to minimize the amount of material needed, then dP/dW = 0
dP/dW = -6272/W² + 2
0 = -6272/W² + 2
6272/W² = 2
cross multiply
6272 = 2W²
W² = 3136
W = √3136
W = 56ft
Since A = LW
3136 = 56L
L = 3136/56
L = 56ft
Hence the dimensions of the rectangular pen that minimize the amount of material needed is 56ft by 56ft
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