The two number are 39 and 13
<em><u>Solution:</u></em>
Let the two numbers be "a" and "b"
Let the larger number be "a" and the smaller number be "b"
<em><u>Given that, sum of two numbers is 52</u></em>
a + b = 52 ---------- eqn 1
<em><u>One number is 3 times as large as the other number</u></em>
Larger number = 3 times smaller number
a = 3b -------- eqn 2
<em><u>Let us solve eqn 1and eqn 2</u></em>
<em><u>Substitute eqn 2 in eqn 1</u></em>
3b + b = 52
4b = 52
b = 13
<em><u>Substitute b = 13 in eqn 2</u></em>
a = 3(13)
a = 39
Thus the two number are 39 and 13
Answer:
x> 5/4
Step-by-step explanation:
9<4(x+9)−7−25
Step 1: Simplify both sides of the inequality.
9<4x+4
Step 2: Flip the equation.
4x+4>9
Step 3: Subtract 4 from both sides.
4x+4−4>9−4
4x>5
Step 4: Divide both sides by 4.
4x/4>5/4
x>5/4
pls give brainliest
No I think it’s a 90 degree rotation because the notations above PQR indicates only 1 rotation...
Since that is a triangle the expression would be b x h / 2. So 12*12 = 144 / 2 = 72. The answer is 72.
