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Ilia_Sergeevich [38]

2 years ago

8

Ms. De Leon wants to produce different sets of test questions for her essay test. If she plans to do this by putting together 3

out of 5 questions she prepared, how many different sets of questions could she contruct?
A.10
B. 20
C. 60
D. 80

1 answer:

gladu [14]2 years ago

5 0

The correct answer is b

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Matter is in a liquid state when its temperature is between its melting point and its boiling point. Suppose that some substance

alexgriva [62]

Answer:

96.512 °F < x < 591.242 °F

Step-by-step explanation:

We are given;

Melting point = 35.84 °C

Boiling point = 310.69 °C

Now, we are given that formula to convert °C to °F is;

°C = (5/9)°F

Thus if the temperature in Fahrenheit is x, then;

Melting point is; 35.84 °C = (5/9)x°F - "32"

x = ((9 × 35.84)/5) + 32

x = 96.512 °F

Similarly, for Boiling point;

Boiling point is;

310.69 °C = (5/9)x°F - "32"

x = ((9 × 310.69)/5) + 32

x = 591.242 °F

Now, we are told that matter is in its liquid form when it is between melting and boiling point.

Thus, range of x in inequality form is;

96.512 °F < x < 591.242 °F

6 0

2 years ago

5 3/2 x 3 6/7 you have 10 point to do the answer

pogonyaev

Step-by-step explanation:

Conversion a mixed number 5 3/2

to an improper fraction: 5 3/2 = 5 3/2

= 5 · 2 + 3/2

= 10 + 3/2

= 13/2

To find a new numerator:

a) Multiply the whole number 5 by the denominator 2. Whole number 5 equally 5 * 2/2

= 10/2

b) Add the answer from previous step 10 to the numerator 3. New numerator is 10 + 3 = 13

c) Write a previous answer (new numerator 13) over the denominator 2.

Five and three halfs is thirteen halfs

Conversion a mixed number 3 6/7

to an improper fraction: 3 6/7 = 3 6/7

improper fraction: 3 6/7 = 3 6/7

3 · 7 + 6/7 = 21 + 6/7 =27/7

To find a new numerator:

a) Multiply the whole number 3 by the denominator 7. Whole number 3 equally 3 * 7/7

= 21/7

b) Add the answer from previous step 21 to the numerator 6. New numerator is 21 + 6 = 27

c) Write a previous answer (new numerator 27) over the denominator 7.

Three and six sevenths is twenty-seven sevenths

Multiple:

13/2 * 27/7 = 13/2 · 27/7 = 351/14

3 0

2 years ago

X∞n=0<br> (2<br> n + 1)<br> x<br> 2<br> n

Black_prince [1.1K]

Answer:3

If x=0 or x=1 it is trivial, so 0<x<1. Define a=1−x2, then 0<a<1.

Step-by-step explanation:

6 0

2 years ago

Evaluate the surface integral:S

rjkz [21]

Assuming $S$ does not include the plane $z=0$ , we can parameterize the region in spherical coordinates using

$\mathbf r(u,v)=\left\langle3\cos u\sin v,3\sin u\sin v,3\cos v\right\rangle$

where $0\le u\le2\pi$ and $0\le v\le\dfrac\pi/2$ . We then have

$x^2+y^2=9\cos^2u\sin^2v+9\sin^2u\sin^2v=9\sin^2v$
$(x^2+y^2)=9\sin^2v(3\cos v)=27\sin^2v\cos v$

Then the surface integral is equivalent to

$\displaystyle\iint_S(x^2+y^2)z\,\mathrm dS=27\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^2v\cos v\left\|\frac{\partial\mathbf r(u,v)}{\partial u}\times \frac{\partial\mathbf r(u,v)}{\partial u}\right\|\,\mathrm dv\,\mathrm du$

We have

$\dfrac{\partial\mathbf r(u,v)}{\partial u}=\langle-3\sin u\sin v,3\cos u\sin v,0\rangle$
$\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle3\cos u\cos v,3\sin u\cos v,-3\sin v\rangle$
$\implies\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle-9\cos u\sin^2v,-9\sin u\sin^2v,-9\cos v\sin v\rangle$
$\implies\left\|\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}\|=9\sin v$

So the surface integral is equivalent to

$\displaystyle243\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv\,\mathrm du$
$=\displaystyle486\pi\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv$
$=\displaystyle486\pi\int_{w=0}^{w=1}w^3\,\mathrm dw$

where $w=\sin v\implies\mathrm dw=\cos v\,\mathrm dv$ .

$=\dfrac{243}2\pi w^4\bigg|_{w=0}^{w=1}$
$=\dfrac{243}2\pi$

4 0

2 years ago

What are 5 applications of Geometry in real life?

Xelga [282]

Answer:

•construction of buildings

•Interior designs

•Art

•Measuring of orbits and planetary •motions Interior designs

4 0

2 years ago