Answer:
[x+6y+2z][x²+(6y)²+(2z)²-6xy-12yz-2xz]
Step-by-step explanation:
x³+216y³+8z³-36xyz
x³+(6y)³+(2z)³-3×6×2×xyz
As we know
a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ca)
Let a=x
b=6y
c=2z
Now.
[x+6y+2z][(x²+(6y)²+(2z)²-x×6y-6y×2z-x×2z]
[x+6y+2z][x²+(6y)²+(2z)²-6xy-12yz-2xz]
Answer:
3 < c < 9
Step-by-step explanation:
The length of a side of a triangle cannot be negative. This eliminates the first and last options.
The addition of two sides of a triangle must be greater than the third side. In this case:
3 + 6 = 9 > c
So, the second option is correct. The third option is not correct, because, for example, c = 8 is possible
(-7,-8) is the center and 8 is the radius.
The percent will be 481.8 so that will be the nearest tenth of a percent Hopes this help times or do simplfy.
Answer:
Step-by-step explanation:
I can solve 4 for you.
a - 3a
1a - 3a
= 2a