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valentina_108 [34]
3 years ago
10

LA BASE DE UN RECTANGULO ES 8 M MAYOR QUE LA ALTURA, EL AREA MIDE 65 METROS CUADRADOS ¿CUANTO MIDEN LA BASE Y ALTURA?

Mathematics
1 answer:
sp2606 [1]3 years ago
4 0

Answer:

23 m and 15 m

Step-by-step explanation:

THE BASE OF A RECTANGLE IS 8 M GREATER THAN THE HEIGHT, THE AREA MEASURES 65 SQUARE METERS HOW MUCH DO THE BASE AND HEIGHT MEASURE?

Let the height of the rectangle is h.

Base = 8+h

Area of the rectangle, A = 65 m²

We need to find the base and height of the rectangle. The area of a rectangle is given by :

A = bh

So,

65=(8+h)\times h\\\\65=8h+h^2\\\\h^2+8h-65=0\\\\(h-5)(h+13)=0\\\\h=5\ m\ \text{and}\ x=-13\ m

Neglecting negative value, h = 15 m

Base  = 8+15 = 23 m

So, the base and height of the rectangle is 23 m and 15 m respectively.

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​claim: the mean pulse rate​ (in beats per​ minute) of adult males is equal to 6969 bpm. for a random sample of 125125 adult​ ma
RoseWind [281]

Answer:

t=0.21

Step-by-step explanation:

Given  \bar x=69.2, s=10.9, n=125and a population mean \mu=69.

#We state our hypothesis as:

H_o:\mu=69\\\\H_a:\mu\neq 69

The evidence available should validate either the null or alternative hypothesis.

#We calculate the test statistic as:

t=\frac{\bar x-\mu_}{s/\sqrt{n}}\\\\\\=\frac{69.2-69}{10.9/\sqrt{125}}\\\\\\=0.2051

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4 0
3 years ago
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vladimir2022 [97]

Answer:

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8 0
3 years ago
What is the solution to the system of equations below? y = negative one-third x + 9 and y = two-thirds x minus 12 (21, 2) (21, –
lora16 [44]

Answer:

(21, 2 )

Step-by-step explanation:

Given the 2 equations

y = - \frac{1}{3} x + 9 → (1)

y = \frac{2}{3} x - 12 → (2)

Substitute (2) into (1)

\frac{2}{3} x - 12 = - \frac{1}{3} x + 9 ( add \frac{1}{3} x to both sides )

x - 12 = 9 ( add 12 to both sides )

x = 21

Substitute x = 21 into either of the 2 equations and evaluate for y

Substituting into (2)

y = \frac{2}{3} × 21 - 12 = 14 - 12 = 2

Solution is (21, 2 )

6 0
4 years ago
1. In circle o, chord AB and tangent CAD are drawn. It is known that mAB=116 . Find each of the
meriva

Given:

m(ar AB) = 116°

To find:

1. The measure of arc BEA.

2. The measure of ∠CAB

3. The measure of ∠BAD

Solution:

1. The measure of arc of full circle is 360°.

m(ar AB) + m(ar BEA) = 360°

116° + m(ar BEA) = 360°

Subtract 116° from both sides.

m(ar BEA) = 244°

2. Using the tangent-chord angle theorem:

$\Rightarrow m\angle CAB = \frac{1}{2} m(ar \ AB)

$\Rightarrow m\angle CAB = \frac{1}{2} \times 116^\circ

⇒ m∠CAB = 58°

3. Using the tangent-chord angle theorem:

$\Rightarrow m\angle BAD = \frac{1}{2} m(ar \ BEA)

$\Rightarrow m\angle BAD = \frac{1}{2} \times 244^\circ

⇒ m∠BAD = 122°

Using the fact that it is supplementary to ∠CAB.

⇒ m∠CAB + m∠BAD = 180°

⇒ 58° + m∠BAD = 180°

Subtract 58° from both sides.

⇒ m∠BAD = 122°

4 0
3 years ago
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