Answer:
k = 3
Explanation:
K independent file servers
Average "uptime" of each server = 98%
<u>To achieve 99.99% probability by the intranet </u>
given that each server has an uptime = 98%
For the intranet to achieve 99.99% probability we have to choose more than 2 servers ( i.e. 3 servers ) incase any of the server goes down.
As each server posses an uptime of 98% it is almost impossible for all 3 servers to go down at the same time hence value of K = 3
Answer:
a. Programmed decisions
Explanation:
We basically have two types of decision:
- Programmed decision
- Non-Programmed decision
Programmed Decision: used for frequent situations of the organization; both internal and external. This decision results in the formulation of rules, procedures, and policies that can be applied in the future.
Non-Programmed Decision: used for unique and ill-structured situations of the organization; both internal and external. They are one-shot decisions. They have been handled by techniques such as judgment, intuition, and creativity.
Answer:
The answer to this question as follows:
1) False
2) False
3) True
Explanation:
The description of the above option as follows
- In option 1, A single character variable must be contained in one quote mark, but it is based on the alphabet, which is a specific device, and the price of a continued character varies from one device to another, that's why it is false.
- In option 2, This option is wrong because in assembly language the identifier value must not exceed the length than 247 characters.
- In option 3, It is correct because in the variable declaration the first char should be a letter, _, @ or $letter. A total of 1-247 characters. The default case is insensitive.
Answer:
see explaination
Explanation:
#include<iostream>
#include<iomanip>
using namespace std;
int main()
{
double temp1,temp2,inc,cel;
int i=1;
while(i==1)
{
i=0;
cin>>temp1>>temp2>>inc;
if(temp2<temp1||inc<=0)
{
i=1;
cout<<"Starting temperature must be <= ending temperature and increment must be >0.0\n";
}
}
cout<<endl;
cout<<setw(15)<<"Fahrenheit"<<setw(15)<<"Celsius";
while(temp1<=temp2)
{
cel=(temp1-32)/1.8;
cout<<endl;
cout<<fixed<<setprecision(3)<<setw(15)<<temp1<<setw(15)<<cel;
temp1+=inc;
}
}
Please kindly check attachment for output.
