Explanation:
10:A program that assigns the sum 20,30,40
20: input 20,30,40
30:sum input
40: print total
End
Answer:
The solution code is written in Python 3:
- def modifyList(listNumber):
- posCount = 0
- negCount = 0
-
- for x in listNumber:
- if x > 0:
- posCount += 1
- else:
- negCount += 1
-
- if(posCount == len(listNumber)):
- listNumber.append(max(listNumber))
-
- if(negCount == len(listNumber)):
- listNumber.append(min(listNumber))
-
- print(listNumber)
-
- modifyList([-1,-99,-81])
- modifyList([1,99,8])
- modifyList([-1,99,-81])
Explanation:
The key step to solve this problem is to define two variables, posCount and negCount, to track the number of positive value and negative value from the input list (Line 2 - 3).
To track the posCount and negCount, we can traverse through the for-loop and create if else statement to check if the current number x is bigger than 0 then increment posCount by 1 otherwise increment negCount (Line 5- 9).
If all number in the list are positive, the posCount should be equal to the length of the input list and the same rule is applied to negCount. If one of them happens, the listNumber will append either the maximum number (Line 11 -12) or append the minimum number (Line 14-15).
If both posCount and negCount are not equal to the list length, the block of code Line 11 -15 will be skipped.
At last we can print the listNumber (Line 17).
If we test our function using the three sets of input list, we shall get the following results:
[-1, -99, -81, -99]
[1, 99, 8, 99]
[-1, 99, -81]
Answer:
Yes, but this must be done before the withdraw deadline
Explanation:
TopHat is an online learning platform. Students register for courses and if they decide not to continue with a course for reasons best known to them, they are allowed a time period usually one to two weeks to drop the courses. They are then reimbursed the fee for that particular course.
But if that time period elapses and they drop the course, that is considered a withdrawal that is not accepted and which no provisions for reimbursements are made.
nums = []
while True:
num = float(input("Enter a number: "))
if num <= 0:
break
nums.append(num)
print("The largest number entered was",max(nums))
I wrote my code in python 3.8. I hope this helps.
Answer:
Option 4 is correct ,=(B2+C9)
Explanation:
In excel a formula starts with an equal sign followed by the expression.
In first option the formula is incorrect inside the brackets. where 4 is equating to bracket. In 2nd option opening and closing brackets are not same. First closing bracket is missing an opening bracket. In third option all the formula is correct except the part where # is used in formula. Hash tags cannot be used in formula as a value. Here in option D B2 and C9 are cell in excel, whereas parentheses are only used for better readability.