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zhannawk [14.2K]
3 years ago
9

Which is a longer distance: 23678 centimeters or 2.3678 kilometers? Explain how you know. Please help! I’ll give give Brainliest

with explanation
Mathematics
2 answers:
brilliants [131]3 years ago
5 0

Answer:

2.3678 kilometers

Step-by-step explanation:

1 km = 100,000 cm

2.3678 * 100,000 = 236, 780

236, 780 > 23,678

Fynjy0 [20]3 years ago
3 0

Answer:

2.3678 kilometers is longer.

Step-by-step explanation:

The rate of conversion is

10 millimeters = 1 centimeter

100 centimeters = 1 meter

1000 meters = 1 kilometer

Therefore, centimeters to kilometers  would be 23678÷ (100× 1000): a smaller to a larger measurement would require division. This results in 0.23678 kilometers, which is shorter than 2.3678 kilometers.

Or, kilometers to centimeters would be, 2.3678 × (100× 1000): a larger to smaller measurement requires multiplication. This results in 236780 centimeters which is longer than 23678 centimeters.

Baseline is 2.3678 kilometers is longer than 23678 centimeters.

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Answer this please... brainliest.........
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Answer:

Her friend is correct

Step-by-step explanation:

40 * 20% = 8

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bill bought a large submarine sandwich and cut it into 8 equal pieces. He ate 1/4 of the sandwich. How can you write how much of
Arturiano [62]
1/4 would be * 2 since 4*2=8 so 1*2=2 so the answer is 2/8 in total
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If logb2=x and logb3=y, evaluate the following in terms of x and y:
Alja [10]

log_b{162} = x + 4y\\\\log_b324 = 2x+4y\\\\log_b\frac{8}{9} = 3x-2y\\\\\frac{log_b27}{log_b16} = 3y-4x

<em><u>Solution:</u></em>

Given that,

log_b2 = x\\\\log_b3 = y --------(i)

<em><u>Use the following log rules</u></em>

Rule 1: log_b(ac) = log_ba + log_bc

Rule 2: log_b\frac{a}{c} = log_ba - log_bc

Rule 3: log_ba^c = clog_ba

a) log_b{162}

Break 162 down to primes:

162 = 2^1 \times 3^4

log_b{162} =log_b 2^1. 3^4\\\\By\ rule\ 1\\\\ log_b{162} = log_b 2^1 +log_b 3^4\\\\By\ rule\ 3\\\\1log_b2 + 4log_b3\\\\1x+4y\\\\x+4y

Thus we get,

log_b162 = x + 4y

Next

b) log_b 324

Break 324 down to primes:

324 = 2^2 \times 3^4

log_b324 = log_b 2^2.3^4\\\\By\ rule\ 1\\\\log_b324 = log_b2^2 + log_b3^4\\\\By\ rule\ 3\\\\log_b324 = 2log_b2 + 4log_b3\\\\From\ (i)\\\\log_b324 = 2x + 4y

Next

c) log_b\frac{8}{9}

By rule 2

log_b\frac{8}{9} = log_b8 - log_b9\\\\log_b\frac{8}{9} = log_b 2^3 - log_b3^2\\\\By\ rule\ 3\\\\log_b\frac{8}{9} =  3 log_b2 - 2log_b3\\\\From\ (i)\\\\log_b\frac{8}{9} =  3x - 2y

Next

d) \frac{log_b27}{log_b16}

By rule 2

\frac{log_b27}{log_b16} = log_b27 - log_b16\\\\ \frac{log_b27}{log_b16} = log_b3^3 - log_b2^4\\\\By\ rule\ 2\\\\ \frac{log_b27}{log_b16} = 3log_b3 - 4log_b2 \\\\From\ (i)\\\\\frac{log_b27}{log_b16} =  3y - 4x

Thus the given are evaluated in terms of x and y

3 0
3 years ago
If 600 cm2 of material is available to make a box with a square base and a closed top, find the maximum volume of the box in cub
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Answer:

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and then also in step 3 compensating the error in step 2

Step-by-step explanation:

I think I just answered this for another post.

sin(a - b) = sin(a)cos(b) - cos(a)sin(b)

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sin(A - 3pi/2) = sin(A)cos(3pi/2) - cos(A)sin(3pi/2)

but step 2 suddenly and incorrectly switched that central "-" to a "+".

yes, sin(3pi/2) = -1, but that is still an explicit factor in step 2. so it was not used to flip the central operation from subtraction to addition, and therefore this change was a mistake.

then, in step 3, another error was made by just ignoring the "-" sign of "-1" and still keeping the central "+" operation. this error compensated for the error in step 2 bringing us back by pure chance to the right result.

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