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Snowcat [4.5K]
3 years ago
11

A man has a wife with six children and

Mathematics
1 answer:
BartSMP [9]3 years ago
8 0

Answer:

i)10\% \: of \: 8500 \\  =  \frac{1}{10}  \times 8500 \\  = 850 \: was \: his \: tax

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An artificial lake is in the shape of a rectangle and has an area of 9/20 square mile. The width of the lake is 1/5 the length o
Zina [86]
X=width of the lake
y=length of the lake.
we set out this system of equiations
x*y=9/20
x=y/5
we solve by sustitution method
(y/5)*y=9/20
y²/5=9/20
y²=(5*9)/ 20
y²=2.25
y=√2.25=1.5

x=y/5
x=1.5/5=0.3

Solution:
width of the lake=0.3 miles
lenght of the lake=1.5 miles
6 0
3 years ago
Will mark brainliest
victus00 [196]

Answer:

2

Step-by-step explanation:

8 times 1/4 equals 2

if this is wrong i am so sorry

3 0
3 years ago
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A bakery sold a total of 400 cupcakes in a day, and 43% of them were vanilla flavored. how many of the cupcakes sold that day we
garik1379 [7]

The number of the cupcakes sold that day that were vanilla flavored is 172.

<h3>How do we calculate a number from a percentage?</h3>

The number of the cupcakes sold that day that were vanilla flavored can be calculated using the following formula:

Number of vanilla flavored cupcakes sold = Total number of cupcakes sold * Percentage that were vanilla flavored .............. (1)

Substituting the relevant values into equation (1), we have:

Number of vanilla flavored cupcakes sold = 400 * 43% = 172

Learn more about percentages here: brainly.com/question/14801224.

#SPJ1

7 0
2 years ago
IM CONFUSED. WILL GIVE BRANLIEST What is the value of x?
Katen [24]

Answer:

i'd say it's x=6

Step-by-step explanation:

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5 0
3 years ago
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Use the algebraic procedure explained in section 8.9 in your book to find the derivative of f(x)=1/x. Use h for the small number
Triss [41]

Answer:

By definition, the derivative of f(x) is

lim_{h\rightarrow 0}\frac{f(x+h)-f(x)}{h}

Let's use the definition for f(x)=\frac{1}{x}

lim_{h\rightarrow 0} \frac{\frac{1}{x+h}-\frac{1}{x}}{h}=\\lim_{h\rightarrow 0} \frac{\frac{x-(x+h)}{x(x+h)}}{h}=\\lim_{h\rightarrow 0} \frac{\frac{(-1)h}{x^2+xh}}{h}=\\lim_{h\rightarrow 0} \frac{(-1)h}{h(x^2+xh)}=\\lim_{h\rightarrow 0} \frac{-1}{x^2+xh)}=\frac{-1}{x^2+x*0}=\frac{-1}{x^2}

Then, f'(x)=\frac{-1}{x^2}

7 0
3 years ago
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