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Masteriza [31]
2 years ago
11

Type the correct answer in each box. Use numerals instead of words.

Mathematics
1 answer:
Natali5045456 [20]2 years ago
7 0

Given:

Consider the given function is f(x)=-(x+1)(x-3)(x+2).

To find:

The remaining zero and y-coordinate of y-intercept.

Solution:

We have,

f(x)=-(x+1)(x-3)(x+2)

For zeros, f(x)=0.

-(x+1)(x-3)(x+2)=0

(x+1)(x-3)(x+2)=0

(x+1)=0,(x-3)=0,(x+2)=0

x=-1,x=3,x=-2

So, three zeros of given function are -1, 3 and -2.

Putting x=0 in the given function, we get

f(0)=-(0+1)(0-3)(0+2)

f(0)=-(1)(-3)(2)

f(0)=-(-6)

f(0)=6

So, the y-coordinate of y-intercept of the given function is 6. It means the y-intercept is at point (0,6).

Therefore, the zeros of the function f(x)=-(x+1)(x-3)(x+2) are –1, 3, and -2 and the y-intercept of the function is located at (0,6).

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