Question

For any integer x, x squared -x will always produce an even value

Answer 1

Answer:

$(x^2 - x)$ will always have an even value.

Step-by-step explanation:

We are given an integer x.

Let x be even, then it can be written in the form x = 2n, where n is an integer.

If we evaluate,

$(x^2 - x) = (2n)^2 - 2n = 4n^2 - 2n = 2(2n^2 - n)$

Thus, it have an even value.

If we take x to be an odd integer, then,it can be written in the form x = 2n+1, where n is an integer.

$(x^2 - x) = (2n+1)^2 - 2n = 4n^2 + 2n = 2(2n^2 + n)$

Thus, it have an even value.

Thus,

$(x^2 - x)$ will always have an even value.

Answer 2

Not at all:

The square of an even number will generate an even number and 
The square of an odd number will generate an odd number