In case of dogs the value 10 is the minimum value. So all the values lie above 10. In total there were 100 dogs.
So for dogs, we can say number of dogs above the value of 10 pound are 100.
In case of Cats, 10 lies at the position of median. Median is the central value and 50% values lie above the median value. So number of cats with weight above 10 pound is 50.
Thus, we can conclude that there were 50 more dogs than the cats with weight over 10 pounds. So option C gives the correct answer.
Is this math? I'm sorry I don't get what formula I'm supposed to rewrite or -
Answer:
61% increase if the airlines held a 50$ baggage fee
Step-by-step explanation:
Three $20 bills is a total of $60
$60 - $12 = $48
He spent a total of $48 on the books
Divide the total spent by the number of books:
48 / 3 = 16
Each book cost $16
The percent error is: 6.89%
Step-by-step explanation:
The percent error is given by:
Here,
Expected Value = $93
Exact Value = $87
Putting the values in the formula
The percent error is: 6.89%
Keywords: Percent, Error
Learn more about percent error at:
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