Each large box weighs 15 kilograms and each small box weighs 13.5 kilograms.
Step-by-step explanation:
Let,
Weight of large box = x
Weight of small box = y
According to given statement;
5x+2y=102 Eqn 1
3x+8y=153 Eqn 2
Multiyplying Eqn 1 by 4
Subtracting Eqn 2 from Eqn 3
Dividing both sides by 17
Putting x=15 in Eqn 2
Dividing both sides by 8
Each large box weighs 15 kilograms and each small box weighs 13.5 kilograms.
Keywords: linear equation, elimination method
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The picture in the attached figure
we know that
the area of the shaded region is equal to
(2/3)*[area of the circle - the area of the triangle]
step 1Find the area of a circle Ac
Ac = π r²
Ac = π (6)²
Ac = 113.10 units²
step 2find the area of the triangle At
The triangle is an equilateral triangle with angles on each corner equal to 60 degrees. Meanwhile,
the 3 angles at the center is 120 degrees each since a circle is 360 degree.
We know that the radius (line from centerpoint to corner) is equivalent to 6.
Using the cosine law,
we can calculate for the length of one side.
s² = 6^ + 6² – 2 (6) (6) cos 120
s² = 108
s = 10.4 units
Since this is an equilateral triangle, therefore, all sides are equal.
The area for this is:
At = (sqrt3 / 4) * s²
At = 46.77 units²
step 3the area of the shaded region=(2/3)*[area of the circle - the area of the triangle]
the area of the shaded region=(2/3)*[113.10-46.77]------> 44.22 units²
therefore
the answer isthe area of the shaded region is 44.22 units²
Answer:
4m3+18m2−34m+12
Step-by-step explanation:
=(4m+−2)(m2+5m+−6)
=(4m)(m2)+(4m)(5m)+(4m)(−6)+(−2)(m2)+(−2)(5m)+(−2)(−6)
=4m3+20m2−24m−2m2−10m+12
Given that
The length of the rectangle 4cm and the breadth is 3cm
Area of rectangle= length * breadth
Area= 4*3
= 12cm^2
Hope it helped
