Answer:
The graph of f has an inflection point at x = 0.
Step-by-step explanation:
An inflection point occurs when the second derivative changes signs. Since f"(x) is decreasing and has an x-intercept at 0, it changes signs from + to -, so there is an inflection point at x = 0.
Expand the square: 4(x-11)^ =25
4(x-11)(x-11)=25
Distribute : 4(x-11)(x-11)=25
4(x(x-11)-11(x-11))=25
Distribute: 4(x(x-11)-11(x-11))=25
4(x^-11x-11(x-11))=25
Solution: x=17/2
x=27/2
hope that helps
No diagram :(
can you upload a picture so we can help out or a description? thanks!
28% of 1.00 = 28
To get your answer, multiply .28 * 100.
28% of $1.00 = 28 cents.
<u>Answer:</u>
A curve is given by y=(x-a)√(x-b) for x≥b. The gradient of the curve at A is 1.
<u>Solution:</u>
We need to show that the gradient of the curve at A is 1
Here given that ,
--- equation 1
Also, according to question at point A (b+1,0)
So curve at point A will, put the value of x and y

0=b+1-c --- equation 2
According to multiple rule of Differentiation,

so, we get



By putting value of point A and putting value of eq 2 we get


Hence proved that the gradient of the curve at A is 1.