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Anastaziya [24]
3 years ago
8

Last month, a sporting goods store sold a total of 100 T-shirts and running shorts. The number of T-shirts sold was 10 more than

twice the number of running shorts sold. How many T-shirts and running shorts did the store sell separately?
A.
T-shirts: 30, Running shorts: 70

B.
T-shirts: 45, Running shorts: 55

C.
T-shirts: 55, Running shorts: 45

D.
T-shirts: 70, Running shorts: 30
Mathematics
2 answers:
mafiozo [28]3 years ago
5 0
D.
30x2=60
60+10 = 70
gladu [14]3 years ago
5 0
A is the answer I think
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Step-by-step explanation:

The inverse of f(x) = x is just y = x.

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A bag contains 20 counters. 8 of the counters are yellow. A counter is picked at random. What is the probability that it is yell
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Given f(x) = -3x - 1, solve for f(x)= -4​
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Marquise has 200200200 meters of fencing to build a rectangular garden.
Lera25 [3.4K]

Answer:

2500 Square meters

Step-by-step explanation:

Given the garden area (as a function of its width) as:

A(w)=-w^2+100w

The maximum possible area occurs when we maximize the area. To do this, we take the derivative, set it equal to zero and solve for w.

A'(w)=-2w+100

-2w+100=0

-2w=-100

w=50 meters

Since Marquise has 200 meters of fencing to build a rectangular garden,

Perimeter of the proposed garden=200 meters

Perimeter=2(l+w)

2(l+50)=200

2l+100=200

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l=50 meters

The dimensions that will yield the maximum area are therefore:

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3 0
3 years ago
A couple plans to have children until they get a​ girl, but they agree they will not have more than three​ children, even if all
barxatty [35]

Answer:

a)Let X be number of children

X=1,2,3

P(X=1)= 0.47

P(X=2) = 0.2491

P(X=3) = 0.942923

b) 3.7970

c) 1.6232

Step-by-step explanation:

The complete question is:

A couple plans to have children until they get a​ girl, but they agree they will not have more than three​ children, even if all are boys. Assume that the probability of having a girl is 47.00​%. ​

a) Create a probability model for the number of children​ they'll have.

X=1,2,3

​P(X=1)=??

P(X=2)= ??

P(X=30=???

​(Round to four decimal places as​ needed

​b) Find the expected number of children.

E(X)= ???

​c) Find the expected number of boys​ they'll have.

Expected number of boys= ???

Solution:

Probability of a girl= 0.47

Probability of a boy= 0.53

a) P(X=1)= 0.47

P(X=2) = 0.47× 0.53= 0.2491

P(X=3)= 0.47× 0.53× 0.53 + 0.53× 0.53× 0.53

             = 0.942923

b) E(number of children)= 1× P(X=1) + 2 ×P(X=2) + 3 × (PX=3)

                                       = 3.796969

c) Y: number of boys

P(Y=1)= 0.53×0.47= 0.2491

P(Y=2) = 0.53×0.53×0.47=0.46375

P(Y=3)= 0.53× 0.53× 0.53= 0.148875

E(Y)= P(Y=1)×1 + P(Y=2)×2 + P(Y=3)×3

       = 0.148875×3 +0.46375×2+0.2491 ×1

      = 1.6232

5 0
3 years ago
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