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Alex787 [66]
3 years ago
9

Can somebody help please and thank you :)

Mathematics
1 answer:
Marizza181 [45]3 years ago
4 0
I can help soo first u need to read the question and see what’s its telling u then u got to see what to did like division adding and the other stuff but u are going to divide
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Write the following numbers in order from least to greatest: -5.6, 7.95, 2.06, 0, -6.89
pashok25 [27]

Answer:

-6.89, -5.6, 0, 2.06, 7.95

Step-by-step explanation:

Hope this helps!

7 0
3 years ago
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Estimate the line of best fit using two points on the line 100 90 80 70 (e, 80) 60 30 20 10 (2.20) 10 O A. y= 2x O B. y = 2x+10
nexus9112 [7]

Answer:

y = 10x

Step-by-step explanation:

Given

The attached plot

Required

The line of the best fit using (8,80) and (2,20)

We have:

(x_1,y_1) = (8,80)

(x_2,y_2) = (2,20)

Calculate slope (m)

m = \frac{y_2 - y_1}{x_2 - x_1}

m = \frac{20 - 80}{2- 8}

m = \frac{-60}{-6}

m = 10

The equation is then calculated using:

y = m(x - x_1) + y_1

y = 10(x - 8) + 80

Expand

y = 10x - 80 + 80

y = 10x

5 0
3 years ago
Samuel took an antique clock that his grandfather had purchased, to be appraised. The appraiser evaluated the current price of t
andrew11 [14]
This is an exponential growth problem. Exponential growth can be expressed mathematically in the following way: 
y=a (1+r)^{t}.
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Parameter r is percentage increase. 
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An equation that would describe given problem is:
y=400 (1+0.02)^{t}
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I attached the graph of this function.

6 0
4 years ago
Given a sample mean difference of 23, a standard error of 4.2, and a critical t value of 2.262, what are the values for the conf
erastova [34]

Answer: (13.4996, 32.5004)

Step-by-step explanation:

The confidence interval for mean difference is given by :-

(\overline{x}_1-\overline{x}_2)\pm t^*\times SE ,

where (\overline{x}_1-\overline{x}_2) = sample mean difference .

t^*= critical t value (two-tailed)

SE= Standard error.

Given : (\overline{x}_1-\overline{x}_2)=23

t^*=2.262

SE= 4.2

Now, the confidence interval for mean difference will be :-

23\pm (2.262)\times (4.2)\\\\= 23\pm9.5004\\\\=(23-9.5004,\ 23+9.5004)\\\\=(13.4996,\ 32.5004)

Hence, the required confidence interval : (13.4996, 32.5004)

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3 years ago
Circumference and area of a circle <br>help me please ​
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A.) The circumference of the tire is 94.2

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