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3 years ago

Enter the x-coordinate of the solution to this system of equations

Mathematics

1 answer:

Kitty [74]3 years ago

5 0

Answer:

equation 2into minus 3 into equation 1

8x+ 3y= -28

-3x-3y=18

----------------

5x=10

x =2

put value of y in equation 2

8 into 2+3y=-28

16+3y= -28

3y= -28+16

3y= -12

y= -4

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Please help

faltersainse [42]

The other one will be 66 degrees because what you do is you see it is a 90 degree angle so then you subtract 24 from 90 and get 66

4 0

4 years ago

Read 2 more answers

3(3u-2)=2(3u+3) What is the steps

sattari [20]

Hopes this helps:

Answer: u = 4

1. Expand.
9u - 6 = 6u + 6

2. Add 6 to both sides.
9u = 6u + 6 + 6

3. Simplify 6u + 6 + 6 to 6u + 12.
9u = 6u + 12

4. Subtract 6u from both sides.
9u - 6u = 12

5. Simplify 9u - 6u to 3u.
3u = 12

6. Divide both sides by 3.
u = 12/3

7. Simplify 12/3 to 4.
u = 4

6 0

3 years ago

In Circle P, m EA=58, m BC=42, m CD=90, find:

elena55 [62]

Circle theorem states that the angle that an arc subtends at the center of a

circle is twice the angle subtended at the circumference.

The values are as follows;

m∠EDA = 90°
m∠BDC = 21°
m∠BEC = 21°
$m\widehat{AB}$ = 80°
m∠AEB = 40°
m∠ECA = 29°
m∠BAC = 21°
$m\widehat{ED}$ = 90°
m∠ECD = 45°
m∠ACB = 40°
m∠EBD = 45°
m∠ADB = 40°
m∠CAD = 45°
m∠EAB = 90°
m∠EBC = 90°

Reasons:

$\displaystyle 1. \ \mathbf{m\angle EDA} = \frac{1}{2} \cdot m\angle EPC$ Angle subtended at center is twice angle at circumference.

m∠EPC = 180°

∴ m∠EDA = 0.5 × 180° = 90°

2. $m\widehat{BC}$ = 42°, therefore, m∠BPC = 42°

$\displaystyle \ m\angle BDC= \frac{1}{2} \cdot m\angle BPC$

m∠BDC = 0.5 × 42° = 21°

3. m∠BEC = m∠BDC = 21°

4. $m\widehat{AB}$ = 180° - (58° + 42°) = 80°

5. $\mathbf{m\widehat{AB}}$ = m∠APB by definition

m∠AEB = 0.5 × m∠APB

m∠AEB = 0.5 × 80° = 40°

6. m∠ECA = 0.5 × m∠AE

Therefore;

m∠ECA = 0.5 × $m\widehat{EA}$

m∠ECA = 0.5 × 58° = 29°

m∠ECA = 29°

7. m∠BAC = 0.5 × $\mathbf{m\widehat{BC}}$

m∠BAC = 0.5 × 42° = 21°

m∠BAC = 21°

8. $m\widehat{ED}$ = 180° - $\mathbf{m\widehat{CD}}$

$m\widehat{ED}$ = 180° - 90° = 90°

$\mathbf{m\widehat{ED}}$ = 90°

9. m∠ECD = 0.5 × $\mathbf{m\widehat{ED}}$

m∠ECD = 0.5 × 90° = 45°

10. m∠ACB = 0.5 × $m\widehat{AB}$

m∠ACB = 0.5 × 80° = 40°

11. m∠EBD = 0.5 × $\mathbf{m\widehat{ED}}$

m∠EBD = 0.5 × 90° = 45°

12. m∠ADB = 0.5 × $\mathbf{m\widehat{AB}}$

m∠ADB = 0.5 × 80° = 40°

13. m∠CAD = 0.5 × $\mathbf{m\widehat{CD}}$

m∠CAD = 0.5 × 90° = 45°

14. m∠EAB = 0.5 × $\mathbf{m\widehat{EABC}}$

m∠EAB = 0.5 × 180° = 90°

15. m∠EBC = 0.5 × $\mathbf{m\widehat{EABC}}$

m∠EBC = 0.5 × 180° = 90°

Learn more about circle theorems here:

brainly.com/question/25101481

3 0

3 years ago

Helen's house is located on a rectangular lot that is1 1-8 miles by 9/10 mile.Estimate the distance around the lot

klemol [59]

Answer: The distance around the lot is given by

$4\frac{1}{20}\ miles$

Step-by-step explanation:

Since we have given that

Length of rectangular lot is given by

$1\frac{1}{8}\\\\=\frac{9}{8}\ miles$

Width of rectangular lot is given by

$\frac{9}{10}\ mile$

We need to find the distance around the lot.

As we know the formula for "Perimeter of rectangle":

$Perimeter=2(Length+Width)\\\\Perimeter=2(\frac{9}{8}+\frac{9}{10})\\\\Perimeter=2(\frac{45+36}{40})\\\\Perimeter=2\times \frac{81}{40}\\\\Perimeter=\frac{81}{20}\\\\Perimeter=4\frac{1}{20}\ miles$

Hence, the distance around the lot is given by

$4\frac{1}{20}\ miles$

3 0

3 years ago

Read 2 more answers

Use the distributive property to simplify the expression.

KatRina [158]

The first one is A while the second one is B
5 + 3(2x +4) + 6
5 + 6x + 12 + 6
5 + 12 + 6 +6x
= 23 + 6x

7 0

3 years ago