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3 years ago

8

1. What is asked in the problem?

1 answer:

Scorpion4ik [409]3 years ago

5 0

Answer:

See Explanation

Step-by-step explanation:

Given

See attachment

Solving (1): What is asked

The requirement of the question is to determine the difference between the amount of sugar used between yesterday and today

Solving (2): The given facts

$Yesterday = \frac{9}{10}kg$

$Today = \frac{3}{5}kg$

Solving (3): Operation to be used

We use subtraction operation

Solving (4): The mathematical sentence

$D = Yesterday - Today$

$D = \frac{9}{10}kg - \frac{3}{5}kg$

D represents the difference

Solving (5): The solution

$D = \frac{9}{10}kg - \frac{3}{5}kg$

Take LCM

$D = \frac{9 - 6}{10}kg$

$D = \frac{3}{10}kg$

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1. What is the solution of n² – 49 = 0? (1 point)

maks197457 [2]

Answer:

1. $n=\pm7$

2. $x=\pm7i[tex]3.[tex]\pm 12x =a$

4. 22

Step-by-step explanation:

1. $n^2 - 49 = 0$

$n^2 =49$

$n= \sqrt{49}$

$n=\pm7$

2. $x^2+64 = 0$

$x^2 =-64$

$x= \sqrt{49}$

$x=\pm7i[tex]3. Area of square = [tex]a^{2}$

Where a is the side

We are given an area o square = $144x^{2}$

So, $144x^{2}=a^{2}$

$\sqrt{144x^{2}}=a$

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4. We are given that the solution of quadratic equation -9 and 9

So, equation becomes:

$(x+9)(x-9)=0$

$x^2- 81=0$

So, in the given equation $x^2 + z = 103$

z should be the number from which if we subtract 103 so we get 81

Substitute z = 22

$x^2 + 22 = 103$

$x^2 + 22 -103=0$

$x^2 -81=0$

Thus the value of z is 22

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