Mark jogged 0.6 miles. Caroline jogged 0.49 miles. Write an inequality to compare the distances they jogged

a normal distribution has a mean of 56 and a standard deviation of 8. Find the percentage of data values that are in the given i

vekshin1

Answer:

12) Between 40 and 64 = 0.815

13) Between 32 and 40 = 0.0235

14) Between 56 and 64 = 0.34

15) At most 56 = 0.515

16) At least 72 = 0.025

17) At most 64 = 0.855

Explanation:

To answer this, we will convert each of the values into their standardized form to make this easier.

The standardized score for any value is the value minus the mean then divided by the standard deviation.

z = (x - μ)/σ

x = Each value

μ = Mean = 56

σ = Standard deviation = 8

12) Between 40 and 64

For 40,

z = (x - μ)/σ = (40 - 56)/8 = (-16/8) = -2

For 64

z = (x - μ)/σ = (64 - 56)/8 = (8/8) = 1

So,

Between 40 and 64 = Between -2 and 1

From the curve, noting that the central point is the mean, with standard score of 0, the lines before it move in step of 1 standard deviation towards the negative side, that is, -1, -2, etc. And the lines before the central point move towards the positive side, that is, 1, 2, 3, etc.

So,

Between -2 and 1 = 0.135 + 0.34 + 0.34 = 0.815

13) Between 32 and 40

For 32,

z = (x - μ)/σ = (32 - 56)/8 = (-24/8) = -3

For 40,

z = (x - μ)/σ = (40 - 56)/8 = (-16/8) = -2

So,

Between 32 and 40 = Between -3 and -2 = 0.0235

14) Between 56 and 64

For 56,

z = (x - μ)/σ = (56 - 56)/8 = (0/8) = 0

For 64,

z = (x - μ)/σ = (64 - 56)/8 = (8/8) = 1

Between 56 and 64 = Between 0 and 1 = 0.34

15) At most 56

For 56,

z = (x - μ)/σ = (56 - 56)/8 = (0/8) = 0

At most 56 = At most 0 = 0.0015 + 0.0235 + 0.15 + 0.34 = 0.515

All the regions before z = 0)

16) At least 72

For 72,

z = (x - μ)/σ = (72 - 56)/8 = (16/8) = 2

At least 72 = At least 2 = 0.0235 + 0.0015 = 0.025

(All the regions from z = 2 to the end)

17) At most 64

For 64,

z = (x - μ)/σ = (64 - 56)/8 = (8/8) = 1

At most 64 = At most 1 = 0.0015 + 0.0235 + 0.15 + 0.34 + 0.34 = 0.855

(All the regions before z = 1)

Hope this Helps!!!

4 0

3 years ago

Directions in picture.

densk [106]

Use PEMDAS, the answer that I got is 19.

8 0

3 years ago

Read 2 more answers

What is Xavier’s available lot coverage?

slavikrds [6]

Answer:

Step-by-step explanation:

<h3>At first:</h3>

Given,

Back of lot of the trapezoid = 175

Front of lot of the trapezoid = 185

Length of lot of the trapezoid = 100

Therefore, 

Area of the trapezoid

$= \frac{a + b}{2} c$

[On putting the values]

$= \frac{175 + 185}{2} \times 100$

[On Simplification]

= 360 × 50

[On multiplying]

= 18000

Hence,

We got the Total Area as 18000.

As per given equation,

$\frac{40}{100} = \frac{x}{total \: area}$
To find the value of x

Solution ,

$= > \frac{40}{100} = \frac{x}{total \: area}$

[On putting Total Area = 18000]

$= > \frac{40}{100} = \frac{x}{18000}$

[On cross multiplication]

=> 40 × 18000 = 100 × x

[On Simplification ]

=> 720000 = 100x

[On dividing both sides with 100]

$= > \frac{720000}{100} = \frac{100x}{100}$

[On Simplification ]

=> x = 7200

Hence,

Xavier's avaliable lot coverage (x) = 7200 (Ans)

7 0

3 years ago

Which digit represents "hundreds" in the number 8732?

masya89 [10]

Our primary counting system is based on binary digits to represent numbers

4 0

3 years ago

Twelve friends will share the cost of a vacation rental property that costs $1,380 a month.

boyakko [2]

Each person will pay $115 because $1,380 divided by 12 is 115

7 0

3 years ago