Question

Find the distance between (3,4) and (4,-6) if necessary, round to the nearest tenth.

Answer 1

Answer:

The distance is:

d = 10.0 units (Rounded to the nearest the Tenths Place)

Step-by-step explanation:

Given the points

• (3,4)

• (4,-6)

The distance 'd' between (3,4) and (4,-6)

$\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):$

$d=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

substituting the points values

   $=\sqrt{\left(4-3\right)^2+\left(-6-4\right)^2}$

   $=\sqrt{1+10^2}$

   $=\sqrt{1+100}$

   $=\sqrt{101}$

   $=10.0$  units (Rounded to the nearest the Tenths Place)

Thus, the distance is:

d = 10.0 units (Rounded to the nearest the Tenths Place)