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3 years ago

Solve the two-step equation and identify the steps. 2 = -7/4+1/4x

Mathematics

2 answers:

GaryK [48]3 years ago

7 0

Answer:

Step-by-step explanation:

IgorC [24]3 years ago

7 0

1. Add 7/4 to both sides.

2. Multiply both sides by 4.

The solution is x =15

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Solve for x<br> 4(x−3)=8(x−1)

ikadub [295]

Answer:

x=-1

Step-by-step explanation:

4(x−3)=8(x−1)

Distribute

4x - 12 = 8x -8

Subtract 4x

4x-12 -4x= 8x-8-4x

-12 = 4x-8

Add 8 to each side

-12+8 = 4x-8+8

-4 = 4x

Divide by 4

-4/4 = 4x/4

-1 =x

8 0

2 years ago

Read 2 more answers

Please help 15 points

Gre4nikov [31]

Answer:

i really don’t know ,

sorry , I’m so sorry

7 0

3 years ago

Suppose that the population of a town Increases by 3% each year. the population of the town today is 25,000

jolli1 [7]

Answer:

The population of town after 1 year is 25,750 .

Step-by-step explanation:

Given as :

The rate of increase in the population of town each year = 3 %

The initial population of town = 25,000

Let the population of town after one year = x

So,

The population after n year = initial population × $(1+\dfrac{\textrm rate}{100})^{\textrm n}$

Or, The population after 1 year = 25,000 × $(1+\dfrac{\textrm 3}{100})^{\textrm 1}$

Or, The population after 1 year = 25,000 × $(1.03)^{1}$

Or, The population after 1 year = 25,000 × 1.03

∴ The population after 1 year = 25,750

Hence The population of town after 1 year is 25,750 . Answer

3 0

3 years ago

Use trigonometric ratios to find the indicated side

iragen [17]

Answer:

a = 139.1

b = 56.2

Step-by-step explanation:

A. Reference angle = 68°

Opp = a

Hyp = 150

Therefore:

Sin 68 = opp/hyp

Sin 68 = a/150

150*sin 68 = a

a = 139.1 (nearest tenth)

B. Reference angle = 68°

Adj = b

Hyp = 150

Therefore:

Cos 68 = adj/hyp

Cos 68 = b/150

150*cos 68 = b

b = 56.2 (nearest tenth)

4 0

2 years ago

The mosquito population is a function of rainfall, and can be approximated by the formula N(x)=−x3+45x2+1000 where x is the numb

KiRa [710]

Answer:

Therefore the population will be maximum when x=30 inches.

Step-by-step explanation:

Given that, the mosquito population is a function of rainfall and can be approximated by the formula

$N(x)= -x^3+45x^2+1000$

where x is the number of inches of rainfall.

$N(x)= -x^3+45x^2+1000$

Differentiating with respect to x

$N'(x)= -3x^2+90x$

Again differentiating with respect to x

$N''(x)=-6x+90$

Now we set N'(x)=0

$-3x^2+90x=0$

$\Rightarrow -3x(x-30)=0$

$\Rightarrow x=0,30$

$N''(0)=-6.0+90=90>0$

$N''(30)=-6.30+90=-90$

Since at x=30, N''(x)<0, So at x=30, N(x) has maximum value.

Therefore the population will be maximum when x=30 inches.

5 0

2 years ago