Answer: 
Step-by-step explanation:
Here the total numbers are 1, 4, 3, 7, 6
Since the total number of possible arrangement = 
The total number of the odd numbers in the given numbers = 3
Thus the possible arrangement that the first three digits will be odd numbers = 
Thus, the probability that the first three digits of Irvings ID number will be odd numbers = the possible arrangement that the first three digits will be odd numbers / total possible arrangement = 
= 
We can one theorem to help us find rational roots of this polynomial.
2x^3 + x^2 - 4x - 2
We'll use Descartes' rule of signs.
Because there is 1 sign change, 1 of the 3 roots will be positive.
Now we can make the value of x -1 to see how many negative roots there will be.
-2 + 1 + 4 - 2
There are 2 sign changes, so we know there will be 2 negative roots.
Because of this, we should have 3 real, rational roots.
Answer:
Step-by-step explanation:
Match the circles on the left with circles on the right. Divide any remaining circles evenly between the remaining squares. See below for one way to do this.
Let, the integers = x, x + 2, x+ 4
It is given that, x + x+2 + x+4 = -198
3x + 6 = -198
3x = -198 - 6
x = -204/3
x = -68
Largest number, x+4 = -68+4 = -64
In short, Your Answer would be: -64
Hope this helps!
Answer:
y= -11
Step-by-step explanation:
After rearranging equation 2, we get x= y+3/2
Sub it into equation 1
y= 3(y+3/2) + 1
y= 3y+9/2 + 1
y= 3y + 11 / 2
2y = 3y + 11
-y = 11
y = -11
