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3 years ago

11

Rose uses the following recipe for crispy rice treats. She decides to make LaTeX: 1\frac{1}{2}1 1 2 of the recipe

1 answer:

lina2011 [118]3 years ago

4 0

Answer:

SLONG in kitty

Step-by-step explanation:

that makes kids not geniuses

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your family went out to dinner to celebrate your grandmas 100th birthday. The total for the dinner was $208.60, so your parents

Allushta [10]

Answer:

$\%Tip = 13.04\%$

Step-by-step explanation:

Given

$Tip= \$31.29$

$Bill = \$208.60$

Required

Determine the percentage of the tip

First, we calculate the amount paid

$Amount = Tip + Bill$

$Amount = \$31.29 + \$208.60$

$Amount = \$239.89$

The percentage of the tip is then calculated using:

$\%Tip = \frac{Tip}{Amount} * 100\%$

$\%Tip = \frac{31.29}{239.89} * 100\%$

$\%Tip = \frac{31.29* 100}{239.89} \%$

$\%Tip = \frac{3129}{239.89} \%$

$\%Tip = 13.04\%$

8 0

2 years ago

At George Washington High School, 119 students walk to school. If this number is 35% of school enrollment, then how many student

nignag [31]

Answer: 340 students

Step-by-step explanation:

The number of students walking to school is 119 and this is 35% of the total number of students.

Assume the total number is denoted by "x".

That would mean that the following formula captures the situation:

119 = 35% * x

119 = 0.35x

x = 119/ 0.35

= 340 students

4 0

3 years ago

Standard Error from a Formula and a Bootstrap Distribution Sample A has a count of 30 successes with and Sample B has a count of

tia_tia [17]

Answer:

Using a formula, the standard error is: 0.052

Using bootstrap, the standard error is: 0.050

Comparison:

The calculated standard error using the formula is greater than the standard error using bootstrap

Step-by-step explanation:

Given

Sample A Sample B

$x_A = 30$ $x_B = 50$

$n_A = 100$ $n_B =250$

Solving (a): Standard error using formula

First, calculate the proportion of A

$p_A = \frac{x_A}{n_A}$

$p_A = \frac{30}{100}$

$p_A = 0.30$

The proportion of B

$p_B = \frac{x_B}{n_B}$

$p_B = \frac{50}{250}$

$p_B = 0.20$

The standard error is:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * (1 - 0.30)}{100} + \frac{0.20* (1 - 0.20)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * 0.70}{100} + \frac{0.20* 0.80}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.21}{100} + \frac{0.16}{250}}$

$SE_{p_A-p_B} = \sqrt{0.0021+ 0.00064}$

$SE_{p_A-p_B} = \sqrt{0.00274}$

$SE_{p_A-p_B} = 0.052$

Solving (a): Standard error using bootstrapping.

Following the below steps.

Open Statkey
Under Randomization Hypothesis Tests, select Test for Difference in Proportions
Click on Edit data, enter the appropriate data
Click on ok to generate samples
Click on Generate 1000 samples ---- <em>see attachment for the generated data</em>

From the randomization sample, we have:

Sample A Sample B

$x_A = 23$ $x_B = 57$

$n_A = 100$ $n_B =250$

$p_A = 0.230$ $p_A = 0.228$

So, we have:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.23 * (1 - 0.23)}{100} + \frac{0.228* (1 - 0.228)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.1771}{100} + \frac{0.176016}{250}}$

$SE_{p_A-p_B} = \sqrt{0.001771 + 0.000704064}$

$SE_{p_A-p_B} = \sqrt{0.002475064}$

$SE_{p_A-p_B} = 0.050$

5 0

2 years ago

Help me please i dont understand

matrenka [14]

Answer:

22

Step-by-step explanation:

The line where it says 2cm, extend that line to the top. You know have 2 triangles, call the one on the left A and the one on the right B

area of recntangle = bh

Rect A:

b = 5

h = 4 - 2

h = 2

bh = 5 x 2

bh = 10

Rect B:

b = 3

h = 4

bh = 4 X 3

bh = 12

Total = 10 + 12

Total = 22

5 0

1 year ago

What happens to the Law of Cosines if the known angle is 90 degrees?

poizon [28]

Answer:

See below.

Step-by-step explanation:

It transforms to the Pythagoras theorem.

c^2 = a^2 + b^2 - 2ab cos C

If C = 90, cos C = zero so the last term disappears.

c^2 = a^2 + b^2 - 2ab * 0

c^2 = a^2 + b^2.

8 0

3 years ago