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3 years ago

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The dimensions of a rectangle are dilated using a scale factor of 3. If the old area is 75 sq. Ft. What is the area of the new r

ectangle

1 answer:

Law Incorporation [45]3 years ago

3 0

Answer:

225 sq. Ft

Step-by-step explanation:

Key words in the question;

Dilated - This means increased pr expanded

Scale factor of 3 - This basically means multiplied by 3

Old square = 75 sq. Ft

This means;

New are = Old area * 3

New area = 75 * 3 = 225 sq. Ft

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A rectangle has a length of 12 yards less than 3 times its width. If the area of the rectangle is 135 square yards, find the len

Aleonysh [2.5K]

Answer:

The length is 15 yards

Step-by-step explanation:

Given

Represent the width with W and length with L: So

$Area = 135yd^2$

$L=3W - 12$

Required

Determine the length of the rectangle:

Area is calculated as thus:

$Area = L * W$

Substitute 3W - 12 for L and 135 for Area

$135= (3W - 12) * W$

$135= 3W^2 - 12W$

Reorder:

$3W^2 - 12W - 135= 0$

Divide through by 3

$W^2 - 4W - 45 = 0$

Expand:

$W^2 - 9W + 5W - 45 = 0$

$W(W - 9) + 5(W - 9) = 0$

$(W + 5)(W-9) = 0$

$W + 5 = 0$ or $W - 9 = 0$

$W = -5$ or $W = 9$

But width can't be negative

So:

$W = 9$

Recall that: $L=3W - 12$

$L = 3 * 9 - 12$

$L = 15$

<em>Hence, the length 15 yards</em>

4 0

3 years ago

At time t ≥ 0, the velocity of a body moving along the s-axis is v = t² -5t +4. When is the body moving backwards

katovenus [111]

Answer:

A

Step-by-step explanation:

The velocity of a moving body is given by the equation:

$v=t^2-5t+4 ,\, t\geq0$

Is the velocity is <em>positive </em>(v>0), then our object will be moving <em>forwards</em>.

And if the velocity is negative (v<0), then our object will be moving <em>backwards</em>.

We want to find between which interval(s) is the object moving backwards. Hence, the second condition. Therefore:

$v$

By substitution:

$t^2-5t+4$

Solve. To do so, we can first solve for <em>t</em> and then test values. By factoring:

$(t-4)(t-1)=0$

Zero Product Property:

$t=1, \text{ and } t=4$

Now, by testing values for t<1, 1<t<4, and t>4, we see that:

$v(0)=4>0,\, v(2)=-20$

So, the (only) interval for which <em>v</em> is <0 is the second interval: 1<t<4.

Hence, our answer is A.

7 0

3 years ago

Solve the following Simultaneous equation<br>Using any suitable method<br> x+6y=2, 3x +2y =10

uranmaximum [27]

Answer:

x = 0.5

y = -1/4 or -0.25

Step-by-step explanation:

x + 6y = 2

3x + 2y = 10

Multiply a number by any of the equations to get numbers of the same variable

3x + 18y = 6

3x + 2y = 10

3x - 3x = 0

NB: subtract evenly if u subtract down from top make sure u subtract down from top throughout

16y = -4

16y/16 = -4/16

y = -1/4 or -0.25

to find the x value, any where you see y u put in the y value(-0.25)

So u'll pick just one of the equations above

x + 6(0.25) = 2

x + 1.5 = 2

x = 1.5 + 2

x = 0.5

5 0

3 years ago

Q : <br> what 1:9 x 6 = ?

kow [346]

Answer:

the answer is $\frac{2}{3}$

Step-by-step explanation:

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3 years ago

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Which choice correctly describes this event? I will flip a coin and get heads 10 times in a row

BARSIC [14]

Answer:

B) Unlikely

Step-by-step explanation:

It is Unlikely that this will happen.

4 0

3 years ago

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