Answer:
The number of distinct arrangements is <em>12600</em><em>.</em>
Step-by-step explanation:
This is a permutation type of question and therefore the number of distinguishable permutations is:
n!/(n₁! n₂! n₃! ... nₓ!)
where
- n₁, n₂, n₃ ... is the number of arrangements for each object
- n is the number of objects
- nₓ is the number of arrangements for the last object
In this case
- n₁ is the identical copies of Hamlet
- n₂ is the identical copies of Macbeth
- n₃ is the identical copies of Romeo and Juliet
- nₓ = n₄ is the one copy of Midsummer's Night Dream
Therefore,
<em>Number of distinct arrangements = 10!/(4! × 3! × 2! × 1!)</em>
<em> = </em><em>12600 ways</em>
<em />
Thus, the number of distinct arrangements is <em>12600</em><em>.</em>
Answer:
Take the numbers 50 and 30. Their greatest common factor is 10, since 10 is the greatest factor that both numbers have in common. To find the GCF of greater numbers, you can factor each number to find their prime factors, identify the prime factors they have in common, and then multiply those together.
Step-by-step explanation:
Answer:
Length of the ladder used by worker = 17 feet
Step-by-step explanation:
Given:
Height of the window from the ground = 13 ft
Distance of fence from the building = 3 ft
Distance of ladder from the building = (3+8) = 11 ft
We have to find the length of the ladder.
Let the length of the ladder be 'x'
From the diagram we can also say that 'x' is the hypotenuse of the right angled triangle.
Using Pythagoras formula:
⇒ ![hypotenuse\ 'x' =\sqrt{(perpendicular)^2+(base)^2}](https://tex.z-dn.net/?f=hypotenuse%5C%20%27x%27%20%3D%5Csqrt%7B%28perpendicular%29%5E2%2B%28base%29%5E2%7D)
Here base length = 11 ft
Perpendicular = 13 ft
Plugging the values:
⇒
⇒ ![x=\sqrt{(169+121)}](https://tex.z-dn.net/?f=x%3D%5Csqrt%7B%28169%2B121%29%7D)
⇒ ![x= \sqrt{290}](https://tex.z-dn.net/?f=x%3D%20%5Csqrt%7B290%7D)
⇒
feet
The length of the ladder = 17 feet to its nearest tenth.
Answer: do the math
Step-by-step explanation:
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Let's call the distance from the beach to the playground x.
Let's call the distance from the stand to the parking lot z.
Let's call the base of the biggest triangle in the picture (from the parking lot to the left) y.
Recall the pythagorean theorem: the sum of the squares of the legs of a right triangle is equal to the square of the hypotenuse.
There are three right triangles we can work with.
Triangle with sides 48, x and z. Here z is the hypotenuse so we get the equation
![x^{2} + 48^{2} = z^{2}](https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20%2B%2048%5E%7B2%7D%20%3D%20z%5E%7B2%7D%20)
Triangle with sides 27, x and y. Here y is the hypotenuse so we get
![27^{2} + x^{2} = y^{2}](https://tex.z-dn.net/?f=%2027%5E%7B2%7D%20%2B%20x%5E%7B2%7D%20%3D%20y%5E%7B2%7D%20)
Triangle with sides z, y and (48+27). Here (48+27) is the hypotenuse so we get
![y^{2} + z^{2} = (27+48)^{2}](https://tex.z-dn.net/?f=%20y%5E%7B2%7D%20%2B%20z%5E%7B2%7D%20%3D%20%2827%2B48%29%5E%7B2%7D%20)
. That is,
![y^{2} + z^{2} = 5625](https://tex.z-dn.net/?f=%20y%5E%7B2%7D%20%2B%20z%5E%7B2%7D%20%3D%205625)
We have 3 equations and 3 unknowns (x, y and z). So let's take the last equation:
![y^{2} + z^{2} = 5625](https://tex.z-dn.net/?f=y%5E%7B2%7D%20%2B%20z%5E%7B2%7D%20%3D%205625)
and replace
![z^{2}](https://tex.z-dn.net/?f=%20z%5E%7B2%7D%20)
and
![y^{2}](https://tex.z-dn.net/?f=%20y%5E%7B2%7D%20)
using expressions that contain an expression in terms of x from the first two equations we came up with.
That gives us:
![48^{2} + x^{2} + x^{2} + 27^{2} =5625](https://tex.z-dn.net/?f=%2048%5E%7B2%7D%20%2B%20x%5E%7B2%7D%20%2B%20x%5E%7B2%7D%20%2B%2027%5E%7B2%7D%20%3D5625)
which we solve for x as follows:
![2 x^{2} + 3033 =5625 2x^{2} =2592 x^{2} =1296 x=36](https://tex.z-dn.net/?f=2%20x%5E%7B2%7D%20%2B%203033%20%3D5625%0A2x%5E%7B2%7D%20%20%3D2592%0A%20x%5E%7B2%7D%20%3D1296%0Ax%3D36)
Now that we know x we can substitute 36 for x into the equation
![48^{2} + x^{2} = z^{2}](https://tex.z-dn.net/?f=48%5E%7B2%7D%20%2B%20x%5E%7B2%7D%20%3D%20z%5E%7B2%7D%20)
and solve for z as follows:
![48^{2} + 36^{2} = z^{2} 2304+1296=z^{2} 3600=z^{2} z=60](https://tex.z-dn.net/?f=48%5E%7B2%7D%20%2B%2036%5E%7B2%7D%20%3D%20z%5E%7B2%7D%20%0A2304%2B1296%3Dz%5E%7B2%7D%20%0A3600%3Dz%5E%7B2%7D%20%0Az%3D60)
This means that the distance from the beach to the parking lot is 36 m and the distance from the stand to the parking lot is 60 m.