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3 years ago

14. Alex earns $7.50 per hour by working after school. He should have at least $60 for buying a video

Mathematics

2 answers:

slavikrds [6]3 years ago

8 0

Answer:

7.50x = 60

x = 8

Step-by-step explanation:

He would have to work 8 hours because 8*7.50=60

Hope I helped :)

SVETLANKA909090 [29]3 years ago

6 0

Answer:

8 hours

Step-by-step explanation:

Let h = hours worked.

We want 7.5 times the hours to be “at least” 60 so

7.5h >= 60

that is your inequality.

to solve it...

h >= 60/7.5

h >= 8

he must work at least 8 hours

branlist please

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Mae has a number cube with 6 sides that are numbered 1 through 6. What is the probability that Mae will roll an odd number?

Stels [109]

Answer:

C) $P(E) = \frac{3}{6}$

The probability that Mae will roll an odd number

$P(E) = \frac{3}{6}$

Step-by-step explanation:

Step(i):-

Given that Mae has a number cube with 6 sides that are numbered 1 through 6.

n(S) = { 1,2,3,4,5,6,} = 6

Let 'E ' be the event of odd numbers

Mae will roll an odd number

n(E) = {1, 3, 5} = 3

Step(ii):-

The probability that Mae will roll an odd number

$P(E) = \frac{n(E)}{n(S)} = \frac{3}{6}$

$P(E) = \frac{3}{6}$

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3 years ago

Probabilities with possible states of nature: s1, s2, and s3. Suppose that you are given a decision situation with three possibl

amm1812

Answer:

1. $P(s_1|I)=\frac{1}{11}$

2. $P(s_2|I)=\frac{8}{11}$

3. $P(s_3|I)=\frac{2}{11}$

Step-by-step explanation:

Given information:

$P(s_1)=0.1, P(s_2)=0.6, P(s_3)=0.3$

$P(I|s_1)=0.15,P(I|s_2)=0.2,P(I|s_3)=0.1$

(1)

We need to find the value of P(s₁|I).

$P(s_1|I)=\frac{P(I|s_1)P(s_1)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_1|I)=\frac{(0.15)(0.1)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_1|I)=\frac{0.015}{0.015+0.12+0.03}$

$P(s_1|I)=\frac{0.015}{0.165}$

$P(s_1|I)=\frac{1}{11}$

Therefore the value of P(s₁|I) is $\frac{1}{11}$ .

(2)

We need to find the value of P(s₂|I).

$P(s_2|I)=\frac{P(I|s_2)P(s_2)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_2|I)=\frac{(0.2)(0.6)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_2|I)=\frac{0.12}{0.015+0.12+0.03}$

$P(s_2|I)=\frac{0.12}{0.165}$

$P(s_2|I)=\frac{8}{11}$

Therefore the value of P(s₂|I) is $\frac{8}{11}$ .

(3)

We need to find the value of P(s₃|I).

$P(s_3|I)=\frac{P(I|s_3)P(s_3)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_3|I)=\frac{(0.1)(0.3)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_3|I)=\frac{0.03}{0.015+0.12+0.03}$

$P(s_3|I)=\frac{0.03}{0.165}$

$P(s_3|I)=\frac{2}{11}$

Therefore the value of P(s₃|I) is $\frac{2}{11}$ .

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3 years ago

<img src="https://tex.z-dn.net/?f=5xy%20%7B%20-%20x%7D%20%5E%7B2%7D%20%7Bt%7D%20%20%2B%202xy%20%2B%203x%20%7B%7D%5E%7B2%7D%20t"

fenix001 [56]

Answer: 7xy + 2x^2t

Step-by-step explanation:

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2 years ago

Find the mean of the list of data. 49, 65, 41, 38, 87, 55, 95, 106 I can’t find the answer

KatRina [158]

Answer:

67.

Step-by-step explanation:

First we find the mean:

Mean is add up everything and divide by how much numbers there are.

The numbers are:

$49, 65, 41, 38, 87, 55, 95, 106$ .

So we add them up which is 536.

Then we divide by how much numbers there are.

There are 8 numbers so 536/8 which is 67.

Hope this helps :D

3 0

3 years ago

The length of the longer leg of a right triangle is 20 inches more than twice the length of the shorter leg. The length of the h

Alex17521 [72]

Answer:

Step-by-step explanation:

Let x represent the length of the hypotenuse.

Let y represent the length of the the shorter leg.

Let z represent the length of the longer leg.

The length of the longer leg of a right triangle is 20 inches more than twice the length of the shorter leg. It means that

z = 2y + 20

The length of the hypotenuse is 22 inches more than twice the length of the shorter leg. It means that

x = 2y + 22

We would apply Pythagoras theorem which is expressed as

Hypotenuse² = opposite side² + adjacent side²

Therefore,

(2y + 22)² = y² + (2y + 20)²

(2y + 22)(2y + 22) = y² + (2y + 20)(2y + 20)

= 4y² + 44y + 44y + 484 = y² + 4y² + 40y + 40y + 400

4y² + 88y + 484 = y² + 4y² + 80y + 400

4y² + 88y + 484 = 5y² + 80y + 400

5y² - 4y²+ 80y - 88y + 400 - 484

y² - 8y - 84 = 0

y² + 6y - 14y - 84 = 0

y(y + 6) - 14(y + 6)

y - 14 = 0 or y + 6 = 0

y = 14 or y = - 6

The shorter length cannot be negative hence y = 14 inches

The length of the shorter side is 14 inches.

The length of the hypotenuse is

(2 × 14) + 22 = 50 inches

The length of the longer side is

(2 × 14) + 20 = 48 inches

7 0

3 years ago