M+1/m-4=6/5 it’s for math I need help !!!!!!!!!!!!!!!!!!!!!!
1 answer:
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Answer:
22 more gallons.
Step-by-step explanation:
Given:
Car A's fuel efficiency is 34 miles per gallon of gasoline.
Car B's fuel efficiency is 23 miles per gallon of gasoline.
Question asked:
At those rates, how many more gallons of gasoline would car B consume than car A on a 1,564 miles trip?
Solution:
<u>Car A's fuel efficiency is 34 miles per gallon of gasoline.</u>
<u>By unitary method:</u>
Car A can travel 34 miles in = 1 gallon
Car A can travel 1 mile in =
Car A can travel 1564 miles in =
<u>Car B's fuel efficiency is 23 miles per gallon of gasoline.</u>
Car B can travel 23 miles in = 1 gallon
Car B can travel 1 mile in =
Car B can travel 1564 mile in =
We found that for 1564 miles trip Car A consumes 46 gallons of gasoline while Car B consumes 68 gallons of gasoline that means Car B consumes 68 - 46 = 22 gallons more gasoline than Car A.
Thus, Car B consumes 22 more gallons of gasoline than Car A consumes.
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Hello there! :)
Answer:
Step-by-step explanation:
Distributive property: a(b+c)=ab+ac
PEMDAS
Order of operations
Parenthesis
Exponent
Multiply
Divide
Add
Subtract
Left/Right
First, you add by 4 from both sides of an equation.
Then, you add numbers from left/right.
4+4=8
, which is our final answer.
Hope this helps you!
Have a nice day! :)
:D
-Charlie
Thank you so much! :)
Answer:
- asymptotes: x = -5, x = 5
- zero: x = 0
Step-by-step explanation:
The function of interest is ...
The asymptotes are found where the denominator is zero. It will be zero when either factor is zero, so at x = 5 and x = -5
__
The zeros are found where the numerator is zero. It will be zero for x = 0.
The asymptotes are x=-5, x=5; the zero is x=0.
