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2 years ago

how many bricks each 22 cm long and 15 CM broad will be required to pave a court 30 metre long and 22 wide

Mathematics

2 answers:

____ [38]2 years ago

6 0

Answer:

20,000 bricks

Step-by-step explanation:

length of brick(L)=22cm

breadth of brick(B)=15cm

now,

area of brick(A)=L×B

=22×15s.q.cm

=0.033s.q.m

again,

length of court(l)=30m

breadth of court(b)=22m

now,

area of court(a)=l×b

=30×22s.q.m

=660s.q.m

lastly,

no.of required brick=area of court/area of

brick

=600 s.q.m/0.033s.q.m

=20,000bricks

Artyom0805 [142]2 years ago

3 0

Answer:

BBBBBBBBBBBBBBBBBBBB

Step-by-step explanation:

CAUSE I SAID SO

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3 years ago

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Answer:

Step-by-step explanation:

The thing to realize is that the total of both angles that have x in them is that they add to 145. That's given.

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3 years ago

how many bricks each 22 cm long and 15 CM broad will be required to pave a court 30 metre long and 22 wide​

how many bricks each 22 cm long and 15 CM broad will be required to pave a court 30 metre long and 22 wide