how many bricks each 22 cm long and 15 CM broad will be required to pave a court 30 metre long and 22 wide
2 answers:
Answer:
20,000 bricks
Step-by-step explanation:
length of brick(L)=22cm
breadth of brick(B)=15cm
now,
area of brick(A)=L×B
=22×15s.q.cm
=0.033s.q.m
again,
length of court(l)=30m
breadth of court(b)=22m
now,
area of court(a)=l×b
=30×22s.q.m
=660s.q.m
lastly,
no.of required brick=area of court/area of
brick
=600 s.q.m/0.033s.q.m
=20,000bricks
Answer:
BBBBBBBBBBBBBBBBBBBB
Step-by-step explanation:
CAUSE I SAID SO
You might be interested in
It's A because 7.5 is the starting point but it's not included so that point is circled.
Answer:
perpendicular
Step-by-step explanation:
because of the opposite signs
Answer:
4
Step-by-step explanation:
3^2=9
-2 times 3 = -6
9-6+1=4
There would be
"five ways" to bring three DVD's. If you divide fifteen by three there would be five.
To prove your work:
Hope this helps!
Replace x with and simplify
2x - 10
~Zane
Happy Halloween!
