Question

Four members from a 45​-person committee are to be selected randomly to serve as​ chairperson, vice-chairperson,​ secretary, and treasurer. The first person selected is the​ chairperson; the​ second, the​ vice-chairperson; the​ third, the​ secretary; and the​ fourth, the treasurer. How many different leadership structures are​ possible?

Answer 1

Answer:

3575880

Step-by-step explanation:

We need to use Permutation method,

$nPr= \frac{n!}{(n-r)!}$

Where n is the sample of size and r the combination considered, so

$n=45\\r=4\\45P4= \frac{45!}{(45-4)!}\\45P4 = 3575880$

There is 3575880 possibilities to make leadership structures in that committee