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Over [174]
3 years ago
15

HELP PLEASE HELP I NEED HELP ASAP

Mathematics
1 answer:
jeka57 [31]3 years ago
3 0
V+5=-8+5=-3
V-5=-8-5=-13

Hence the right answers are A and C
You might be interested in
What is the sum of 3x^2÷(x-2) and x^2÷(x-2)
solniwko [45]

3x^2\div(x-2)+x^2\div(x-2)=\dfrac{3x^2}{x-2}+\dfrac{x^2}{x-2}=\dfrac{4x^2}{x-2}

6 0
3 years ago
Please help show work too please thank you
Black_prince [1.1K]
(3x-9) +(x+19)+x=180
5x+10=180
-10=-10
5x=170
5 = 5
x=34

2x+(2x+10)+x=180
5x+10=180
-10=-10
5x=170
5 = 5
x=34

yes they are similar
6 0
4 years ago
Find the perimeter of the following shapes.
DerKrebs [107]

Answer:

4. (a) = 12 m

   (b) = 27 cm

   (c) = 24 mm

   (d) = 18 km

   (e) = 10 m

   (f) = 36 cm

Step-by-step explanation:

Perimeter is sum the distance round a figure.

if a shape has those, they signify that the shape has two side that are equal

a)  4 + 4 + 2 + 2 = 12. The top part is equal to the bottom part signified by those two lines. And the left is equal to the right .

b)  10 + 10 + 7 = 27

c) 5 + 5 + 8 + 6 = 24

d)  3 + 3 + 6 + 6 = 18

e) 2.5 + 2.5 + 2.5 + 2.5 = 10

f) 12 + 7 + 7 + 5 + 5 = 36

If you need any clarification or more explanation pls do mention in the comment section. i would like to help more.

Hope this helps and if it does pls mark as branliest answer thx.

6 0
4 years ago
Do 4x and 15 + x have the same value when x is 5
Andru [333]

Answer:

They have the same value when x=5

Step-by-step explanation:

4x

Let x = 4

4*5 = 20

15+x

Let x =5

15+5 = 20

They have the same value when x=5

7 0
3 years ago
Read 2 more answers
Find the value of x (3/5)^x(5/3)^2x=125/27​
lesya692 [45]

Given:

The equation is

\left(\dfrac{3}{5}\right)^x\left(\dfrac{5}{3}\right)^{2x}=\dfrac{125}{27}

To find:

The value of x.

Solution:

We have,

\left(\dfrac{3}{5}\right)^x\left(\dfrac{5}{3}\right)^{2x}=\dfrac{125}{27}

\left(\dfrac{5}{3}\right)^{-x}\left(\dfrac{5}{3}\right)^{2x}=\dfrac{5\times 5\times 5}{3\times 3\times 3}      [\because \left(\dfrac{a}{b}\right)^{-m}=\left(\dfrac{b}{a}\right)^{m}]

\left(\dfrac{5}{3}\right)^{-x+2x}=\dfrac{5^3}{3^3}          [\because a^ma^n=a^{m+n}]

\left(\dfrac{5}{3}\right)^{x}=\left(\dfrac{5}{3}\right)^{3}

On comparing the exponents, we get

x=3

Therefore, the value of x is 3.

8 0
3 years ago
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