The error is in step 2. if you are performing an operation on one side of the equation, it must be performed on the entire expression. you can’t only divide by 2 on one term, you must do it to everything in the equation. instead, you could add 6 to both sides first, giving you 2x = -4. Then you can divide by 2 on both sides. the answer is -2.
The ratio of 1:6 is 1/6
The ratio of 3:8 is 3/8
The ratio of 2:14 is 1/7
The ratio of 3:42 is 1/14
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Answer:
824.10
Step-by-step explanation:
In geometry, a hypotenuse is the longest side of a right-angled triangle, the side opposite the right angle. The length of the hypotenuse can be found using the Pythagorean theorem, which states that the square of the length of the hypotenuse equals the sum of the squares of the lengths of the other two sides.
<em>It is useful in different situations involving the need to find distance or the measure of an angle.</em>
Use the Pythagorean theorem to calculate the hypotenuse from right triangle sides. Take a square root of sum of squares: c = √(a² + b²)
Answer:
The given sequence 6, 7, 13, 20, ... is a recursive sequence
Step-by-step explanation:
As the given sequence is

- It cannot be an arithmetic sequence as the common difference between two consecutive terms in not constant.
As
, 
As d is not same. Hence, it cannot be an arithmetic sequence.
- It also cannot be a geometrical sequence and exponential sequence.
It cannot be geometric sequence as the common ratio between two consecutive terms in not constant.
As
,
, 
As r is not same, Hence, it cannot be a geometric sequence or exponential sequence. As exponential sequence and geometric sequence are basically the same thing.
So, if we carefully observe, we can determine that:
- The given sequence 6, 7, 13, 20, ... is a recursive sequence.
Please have a close look that each term is being created by adding the preceding two terms.
For example, the sequence is generated by starting from 1.

and

for n > 1.
<em>Keywords: sequence, arithmetic sequence, geometric sequence, exponential sequence</em>
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