Answer:
60.26yd³
Step-by-step explanation:
Since we are not given the diagram, let us assume that;
Length of the base = 5.4yd
Height of the pyramid = 6.2yd
volume of the square pyramid = BH/3
B is the base area = L^2
B = 5.4²
B = 29.16yd²
H = 6.2yd
Get the volume
volume of the square pyramid = 29.16*6.2/3
volume of the square pyramid = 180.792/3
volume of the square pyramid = 60.26yd³
Hence the volume of the square pyramid to nearest hundredth is 60.26yd³
Answer:
1.) No ;
2.) - 0.931
3.) 0.1785
Step-by-step explanation:
Given :
μ = 84.3 ; xbar = 81.9 ; s = 17.3
H0 : μ = 84.3
H1 : μ < 84.3
The test statistic :
(xbar - μ) ÷ (s/√(n))
(81.9 - 84.3) / (17.3/√45)
-2.4 / 2.5789317
= - 0.9306
= - 0.931
Using the test statistic, we could obtain the Pvalue : df = n - 1 ; df = 45 - 1 = 44
Using the Pvalue calculator :
Pvalue(-0.9306, 44) = 0.1785
Using α = 0.05
The Pvalue > α
Then we fail to reject H0; and conclude that there is no significant evidence to support the claim that the mean waiting time is less than 84.3
The answer is 0.3
Do you want me to explain?
x³ + 2x² - x - 2 < 0
x³ - x + 2x² - 2 < 0
x(x² - 1) - 2(x² - 1) < 0
(x - 2)(x² - 1) < 0
(x - 2)(x - 1)(x + 1) < 0
by chacking we get the solution
x ∈ (-∞,-1) ∪ (-1,1)
