Help! Will give the brainiest to the right answer!<br> Algebra!

This is worth 17 points if you show work you will get the Brainliest answer if your unable to show work type it for your explana

marusya05 [52]

Answer:

B****

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

10.

aliina [53]

Answer:

B. If an object is dropped from a height of 38 feet, the function h(t) = –16t2 + 38 gives the height of the object after t seconds.

Step-by-step explanation:

The equation that models the movement of the object is:

Where,

t: time

a: acceleration due to gravity

v0: initial speed

h0: initial height

Suppose that the object falls with zero initial velocity and from a height of 38 feet.

The equation that models the problem is:

Answer:

If an object is dropped from a height of 38 feet, the function h (t) = -16t2 + 38 gives the height of the object after seconds

Answer: If an object is dropped from a height of 38 feet, the function h (t) = -16t2 + 38 gives the height of the object after seconds

Step-by-step explanation:

6 0

2 years ago

A wall with a height of 20 feet is braced with a support post that forms a 30 degree angle with the top of the wall. What is the

dexar [7]

The length of the support post is 40 ft.

<u>Solution:</u>

Given, the height of the wall is 20 ft; support post forms 30 degree

Refer the attached image

Let us name the triangle as ABC where AB is the wall (opposite side) of 20 ft and $\angle A$ is 30 degree ( $\theta$ ) and AC is the length of the post.

To find: The length of the post (AC)

we know the formula, $sin\theta=\frac{opp}{hyp}$ (trigonometric formula)

On substituting the values we get,

$\Rightarrow sin(30^{\circ})=\frac{20}{AC}$

The value of sin 30 degree is 0.5

$\Rightarrow 0.5=\frac{20}{AC}\rightarrow AC=\frac{20}{0.5}\rightarrow AC=40 ft$

3 0

3 years ago

Evaluate using integration by parts

PolarNik [594]

Rather than carrying out IBP several times, let's establish a more general result. Let

$I(n)=\displaystyle\int x^ne^x\,\mathrm dx$

One round of IBP, setting

$u=x^n\implies\mathrm du=nx^{n-1}\,\mathrm dx$

$\mathrm dv=e^x\,\mathrm dx\implies v=e^x$

gives

$\displaystyle I(n)=x^ne^x-n\int x^{n-1}e^x\,\mathrm dx$

$I(n)=x^ne^x-nI(n-1)$

This is called a power-reduction formula. We could try solving for $I(n)$ explicitly, but no need. $n=5$ is small enough to just expand $I(5)$ as much as we need to.