This is the concept of simultaneous equations, the question requires us to solve the system of equations given by:
2x+4y=38
10x+3y=105
from the top equation;
2x=38-4y
dividing through by 2 we get:
x=19-2y......(*)
substituting (*) in the second equation we get:
10x+3y=105
10(19-2y)+3y=105
190-20y+3y=105
collecting like terms we get:
-20y+3y=105-190
-17y=-85
dividing both sides by -17 we get:
(-17y)/(-17)=(-85)/(-17)
y=5
thus
x=19-2y
x=19-2*5
x=19-10
x=9
thus
x=9 and y=5
There is this app called Photomath where you just take a picture of your problem and it tells you the answer and how to solve it and the solving steps
Answer: 1,000,000
Step-by-step explanation: USA test prep
Subtract 7 from both sides
12 - 7 < n
Simplify 12 - 7 to 5
5 < n
Switch sides
<u>n > 5</u>
<u>The </u><u>distance </u><u>between the two objects in 10 years will be </u><u>250 kilometers.</u>
What is Distance?
Distance is the total movement of an object without any regard to direction. We can define distance as to how much ground an object has covered despite its starting or ending point.
We are given:
The rate at which two objects drift apart in 1 year = 25 km
To calculate the distance between the two objects in 10 years, we apply unitary method:
The distance, the two objects has drifted apart in 1 year is 25 km
So, the distance, the two objects has been drifted apart in 10 years, will be = 
Therefore, the distance between the two objects in 10 years will be 250 kilometers.
Learn more about distance
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