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ivanzaharov [21]
3 years ago
10

HELP MEEEEE. IM FAILING GEOMETRY.

Mathematics
1 answer:
labwork [276]3 years ago
5 0

Answer:

good luck

Step-by-step explanation:

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15 Points!<br><br> Find f(x) and g(x) so that the function can be described as y = f(g(x)).
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f(x)=\dfrac{3}{\sqrt{x}}\\\\g(x)=3x+4\\\\\\y=f(g(x))=f(3x+4)=\dfrac{3}{\sqrt{3x+4}}
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Solve the equation 4=t/2.5 t=
julia-pushkina [17]

Answer:

10

Step-by-step explanation:

Multiply 4 by 2.5 to get 10

8 0
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What is the answer for m+12=10
9966 [12]

Answer:

m = -2

Step-by-step explanation:

Since 10 is smaller than 12, we have to subtract to get a negative number.

10 - 12 = -2

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3 years ago
|−9| − |−5| i hate next gen but help pls
Setler79 [48]

Answer:

4

Step-by-step explanation:

\mathrm{-9 = 9, -5 = 5,\:because\:they\:are\:in\:absolute\:value}\\9 - 5 = 4

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Please helppp with this math question &lt;333
Naya [18.7K]

Answer:

The average rate of change of the function g(x)=x^2+10x+18 over the interval -11 \leq x\leq -1 is -1

Step-by-step explanation:

We are given the function g(x)=x^2+10x+18 over the interval -11 \leq x\leq -1

We need to find average rate of change.

The formula used to find average rate of change is : Average \ rate \ of \ change=\frac{g(b)-g(a)}{b-a}

We have b=-1 and a=-11

Finding g(b) = g(-1)

g(x)=x^2+10x+18\\Putting \ x=-1\\g(-1)=(-1)^2+10(-1)+18\\g(-1)=1-10+18\\g(-1)=9

Finding g(a) = g(-11)

g(x)=x^2+10x+18\\Putting \ x=-11\\g(-11)=(-11)^2+10(-11)+18\\g(-1)=121-110+18\\g(-1)=29

Finding average rate of change

Average \ rate \ of \ change=\frac{g(b)-g(a)}{b-a}\\Average \ rate \ of \ change=\frac{9-29}{-1-(-11)}\\Average \ rate \ of \ change=\frac{-10}{-1+11}\\Average \ rate \ of \ change=\frac{-10}{10}\\Average \ rate \ of \ change=-1

So, the average rate of change of the function g(x)=x^2+10x+18 over the interval -11 \leq x\leq -1 is -1

5 0
3 years ago
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