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3 years ago

What are two consecutive even integers that has a sum of -42?

Mathematics

1 answer:

Dafna1 [17]3 years ago

8 0

Answer:

Step-by-step explanation:

$n,\ n+2-\text{two consecutive even integers}\\\\\text{The equation:}\\\\n+(n+2)=-42\\\\n+n+2=-42\qquad\text{subtract 2 from both sides}\\\\2n=-44\qquad\text{divide both sides by 2}\\\\n=-22\\\\n+2=-22+2=-20$

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Can some one help me plz with step by step<br> x^2 + x - 42

Alexeev081 [22]

Answer:

x = 6 or x = -7

Step-by-step explanation:

Solve for x over the real numbers:

x^2 + x - 42 = 0

The left hand side factors into a product with two terms:

(x - 6) (x + 7) = 0

Split into two equations:

x - 6 = 0 or x + 7 = 0

Add 6 to both sides:

x = 6 or x + 7 = 0

Subtract 7 from both sides:

Answer: x = 6 or x = -7

3 0

2 years ago

Which statement best describes the decimal equivalent of 5/9?

padilas [110]

The answer is c

Explanation:
A repeating decimal continues to go with the same number pattern. The terminating decimal stops the number pattern and does not keep repeating. The decimal for 5/9 is 0.5555... and it will keep repeating the number five.

3 0

2 years ago

An industry representative claims that 10 percent of all satellite dish owners subscribe to at least one premium movie channel.

Greeley [361]

Answer: 1) 0.6561 2) 0.0037

Step-by-step explanation:

We use Binomial distribution here , where the probability of getting x success in n trials is given by :-

$P(X=x)=^nC_xp^x(1-p)^{n-x}$

, where p =Probability of getting success in each trial.

As per given , we have

The probability that any satellite dish owners subscribe to at least one premium movie channel. : p=0.10

Sample size : n= 4

Let x denotes the number of dish owners in the sample subscribes to at least one premium movie channel.

1) The probability that none of the dish owners in the sample subscribes to at least one premium movie channel = $P(X=0)=^4C_0(0.10)^0(1-0.10)^{4}$

$=(1)(0.90)^4=0.6561$

∴ The probability that none of the dish owners in the sample subscribes to at least one premium movie channel is 0.6561.

2) The probability that more than two dish owners in the sample subscribe to at least one premium movie channel.

= $P(X>2)=1-P(X\leq2)\\\\=1-[P(X=0)+P(X=1)+P(X=2)]\\\\= 1-[0.6561+^4C_1(0.10)^1(0.90)^{3}+^4C_2(0.10)^2(0.90)^{2}]\\\\=1-[0.6561+(4)(0.0729)+\dfrac{4!}{2!2!}(0.0081)]\\\\=1-[0.6561+0.2916+0.0486]\\\\=1-0.9963=0.0037$

∴ The probability that more than two dish owners in the sample subscribe to at least one premium movie channel is 0.0037.

8 0

2 years ago

A recent survey of 50 executives who were laid off during a recent recession revealed it took a mean of 26 weeks for them to fin

g100num [7]

Answer: $(24.28,\ 27.72)$

Step-by-step explanation:

Given : Sample size : $n=50$

Sample mean : $\overline{x}=26$

Standard deviation : $\sigma =6.2$

Significance level : $\alpha=1-0.95=0.05$

Critical value : $z_{\alpha/2}=1.96$

Formula to find the confidence interval for population mean :-

$\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}\\\\=26\pm(1.96)\dfrac{6.2}{\sqrt{50}}\\\\\approx26\pm1.72\\\\=(26-1.72,\ 26+1.72)\\\\=(24.28,\ 27.72)$

Hence, a 95% confidence interval for the population mean = $(24.28,\ 27.72)$

6 0

2 years ago

Please help I cannot-

Dmitry [639]

Answer:

1922 m cubed

Step-by-step explanation:

Not gonna do that, I did the work and checked it. Should be right

5 0

2 years ago

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