Question

Please help urgent 168 ≥7(-8x+8)

Answer 1

Answer:

$\boxed {x \geq -2}$

Step-by-step explanation:

Solve for the following inequality:

$168 \geq 7(-8x + 8)$

-Divide both sides by $7$:

$\frac{168}{7} \geq -8x + 8$

$24 \geq -8x + 8$

-Switch sides:

$24 \geq -8x + 8$

$-8x + 8 \leq 24$

-Subtract $8$ to both sides:

$-8x + 8 - 8 \leq 24 - 8$

$-8x \leq 16$

-When you are dividing an integer by a negative integer, then the inequality sign changes. So, divide both sides by $-8$:

$\frac{-8x}{-8} \leq \frac{16}{-8}$

$\boxed {x \geq -2}$