Dear Gaby,
Well I would Say that <span>Any line that intersects a given circle at two different points is called a SECANT and </span><span><span>part of secant intercepted between these points is called CHORD</span> of a circle. So basically, </span><span>Both are very same. ... A Chord connects two points on the circumference of a circle. I hope I could help you my friend and Keep on Rockin'
Wishing you some Rockin' Answers,
Mangle</span>
I hope this helps you
if he jogged 22.4 miles in 7 days
he jogged ? miles in 1 day
?.7=22.4
?=22.4/7
?=3.2
Step-by-step explanation:
2 log 4 (1/4i)
.....................
A) Find KM∠KEM is a right angle hence ΔKEM is a right angled triangle Using Pythogoras' theorem where the square of hypotenuse is equal to the sum of the squares of the adjacent sides we can answer the
KM² = KE² + ME²KM² = 8² + (3√5)² = 64 + 9x5KM = √109KM = 10.44
b)Find LMThe ratio of LM:KN is 3:5 hence if we take the length of one unit as xlength of LM is 3xand the length of KN is 5x ∠K and ∠N are equal making it a isosceles trapezoid. A line from L that cuts KN perpendicularly at D makes KE = DN
KN = LM + 2x 2x = KE + DN2x = 8+8x = 8LM = 3x = 3*8 = 24
c)Find KN Since ∠K and ∠N are equal, when we take the 2 triangles KEM and LDN, they both have the same height ME = LD.
∠K = ∠N Hence KE = DN the distance ED = LMhence KN = KE + ED + DN since ED = LM = 24and KE + DN = 16KN = 16 + 24 = 40
d)Find area KLMNArea of trapezium can be calculated using the formula below Area = 1/2 x perpendicular height between parallel lines x (sum of the parallel sides)substituting values into the general equationArea = 1/2 * ME * (KN+ LM) = 1/2 * 3√5 * (40 + 24) = 1/2 * 3√5 * 64 = 3 x 2.23 * 32 = 214.66 units²
