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Sliva [168]
4 years ago
8

Please help!!! Which number line shows the solutions to n > -2?

Mathematics
2 answers:
denis-greek [22]4 years ago
7 0

Answer:

The first one.

Step-by-step explanation:

I'm sorry if it's wong

PolarNik [594]4 years ago
4 0

Answer: the first one

Step-by-step explanation:

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dem82 [27]
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5 cups of sugar

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Simplify: log base 3 (1/3) ...?
yarga [219]
The answer is 1.

log_3( \frac{1}{3} )
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Since log_y(x) =  \frac{log_{10}(x)}{log_{10}(y)}, then: log_3( \frac{1}{3} )= \frac{log_{10} ( \frac{1}{3}) }{log_{10}(3)}
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Since \frac{1}{x} = x^{-1}, then: \frac{log_{10} ( \frac{1}{3}) }{log_{10}(3)} = \frac{log_{10}(3^{-1} )}{log_{10}(3)}
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Since log x^{a} =a*logx, then: \frac{log_{10}(3^{-1} )}{log_{10}(3)}= \frac{-1*log_{10}(3)}{log_{10}(3)}

From here: \frac{-1*log_{10}(3)}{log_{10}(3)}=-1*\frac{log_{10}(3)}{log_{10}(3)}=-1*1 = -1

6 0
3 years ago
How do I evaluate this integral?<img src="https://tex.z-dn.net/?f=%20%5Cint%5Climits%20%7B%20%5Cfrac%7Bx%7D%7Bx%5E4%2B1%7D%20%7D
inessss [21]
One thing you could try is to set x=\sqrt y. This makes y=x^2, so that \mathrm dy=2x\,\mathrm dx, and y^2=x^4. So the integral is

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A "trickier" way to do it is to write

x^4+1=(x^2+\sqrt2x+1)(x^2-\sqrt2x+1)

so you could decompose the integrand into partial fractions. But that's more work than needed.
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4 years ago
PLZZZZZ HLP ME!!!!!!
tiny-mole [99]

it's (f)

Plz. follow me

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3 years ago
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