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skelet666 [1.2K]

3 years ago

6

The table shows the numbers of studeNt at a highschool who take spanish and Chinese. No student take both language what is p (se

nior|spanish)

1 answer:

Anastaziya [24]3 years ago

6 0

Answer:

the answer is X

Step-by-step explanation:

it is x

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(5 + 7) x 5³ pleaseeeeeeeeee help

nekit [7.7K]

Answer:

1500

Step-by-step explanation:

6 0

2 years ago

Factor completely<br> m^2 — Зm — 18

lilavasa [31]

Answer:

(m + 3) (m - 6)

Step-by-step explanation:

Simplify the following:

m^2 - 3 m - 18

The factors of -18 that sum to -3 are 3 and -6. So, m^2 - 3 m - 18 = (m + 3) (m - 6):

Answer: |

| (m + 3) (m - 6)

4 0

3 years ago

What number should replace the question mark?

TiliK225 [7]

Answer:

Just a guess but I think 5

Step-by-step explanation:

The top right square on all boxes is the difference of the second box and the first box which equals the third box. This rule is applied to all of the other boxes so if I'm not wrong the question mark should be 5

3 0

3 years ago

Read 2 more answers

What’s 3/5y+(-6/5y)=

sladkih [1.3K]

Answer:

-3y/5

Step-by-step explanation:

3/5y+(-6/5y)=

Since the denominator is the same, we can add the numerators

3y - 6y

----------------

5

-3y/5

4 0

3 years ago

Read 2 more answers

One urn contains one blue ball (labeled B1) and three red balls (labeled R1, R2, and R3). A second urn contains two red balls (R

marusya05 [52]

Answer:

(a) See attachment for tree diagram

(b) 24 possible outcomes

Step-by-step explanation:

Given

$Urn\ 1 = \{B_1, R_1, R_2, R_3\}$

$Urn\ 2 = \{R_4, R_5, B_2, B_3\}$

Solving (a): A possibility tree

If urn 1 is selected, the following selection exists:

$B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]$

If urn 2 is selected, the following selection exists:

$B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]$

<em>See attachment for possibility tree</em>

Solving (b): The total number of outcome

<u>For urn 1</u>

There are 4 balls in urn 1

$n = \{B_1,R_1,R_2,R_3\}$

Each of the balls has 3 subsets. i.e.

$B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]$

So, the selection is:

$Urn\ 1 = 4 * 3$

$Urn\ 1 = 12$

<u>For urn 2</u>

There are 4 balls in urn 2

$n = \{B_2,B_3,R_4,R_5\}$

Each of the balls has 3 subsets. i.e.

$B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]$

So, the selection is:

$Urn\ 2 = 4 * 3$

$Urn\ 2 = 12$

Total number of outcomes is:

$Total = Urn\ 1 + Urn\ 2$

$Total = 12 + 12$

$Total = 24$

5 0

2 years ago