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Vilka [71]
3 years ago
5

A survey of 40 employees at a company found that 22 of them preferred to eat lunch at their desk rather than at the cafeteria or

outside the office. What percent of the surveyed employees preferred to eat lunch at their desk?
Mathematics
1 answer:
Jet001 [13]3 years ago
6 0

Answer:

55 percent of the surveyed employees preferred to eat lunch at their desk.

Step-by-step explanation:

Here, the total number of surveyed employees  = 40

The number of employees who prefer having lunch at their desk  = 22

Now,\textrm{Percentage of the employees who prefer to do so }  = \frac{\textrm{Number of people who prefer their desk for lunch}}{\textrm{Total employees surveyed}}  \times 100

= \frac{22}{40}  \times 100  =  55

or, Percentage of the employees who prefer to do so = 55%

Hence, 55 percent of the surveyed employees preferred to eat lunch at their desk.

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Write the equation of a line that is perpendicular to y=3x-2 that passes trough the point (-9,5)
ElenaW [278]

\huge\boxed{y-5&=-\frac{1}{3}(x+9)}

First, we'll find the slope of the new line. The first line has a slope of 3. Take the negative reciprocal of this (Flip the numerator and denominator, then multiply by -1) to get -\frac{1}{3} for the new slope.

Then, we'll use the point-slope form to make the new equation, where m is the slope and (x_1,y_1) is a point on the line:

\begin{aligned}y-y_1&=m(x-x_1)\\y-5&=-\frac{1}{3}(x-(-9))\\y-5&=-\frac{1}{3}(x+9)\end{aligned}

3 0
1 year ago
Read 2 more answers
PLEASE HELP QUESTION 3 AND 4. EASY!!!!!!!!!!!!!!
Inessa05 [86]
Answer: 3• D 4• B (why does this require me to put 20 characters) anyway this is my guess





7 0
3 years ago
Use the graph to determine
gtnhenbr [62]

Answer:

a) Domain: x≥0

b) Range:  y≤-2

c) x-intercepts: None

d) y-intercepts: (0,-2)

e) f(4)= -4

Step-by-step explanation:

If this helps please mark as brainliest

5 0
3 years ago
Help me with a. b. c. I need help
hammer [34]

Answer:

a) Perimeter = 20.5 Inches

   Area is 15 Sq Inches

b) Perimeter is 61.4 Cms

    Area is 210 Sq cm

c) Perimeter is 22 yards

   Area is 21 Sq Yards

Step-by-step explanation:

a) Perimeter = sum of all the sides

= 8+7.5+5

=20.5

Perimeter = 20.5 Inches

Area of Triangle =\frac{1}{2} \times height \times Base

Base = 7.5 In

Height = 4 In

A = \frac{1}{2} \times 4 \times 7.5

A = 2 \times 7.5

A = 15

Hence Area is 15 Sq Inches

b)  Perimeter = Sum of all the sides

P=13+23+13.4+12

P=61.4

Perimeter is 61.4 Cms

Area of trapezium = \frac{1}{2} \times height  \times (sum \ of \ parallel \ sides)

A= \frac{1}{2} \times 12 \times (12+23)

A= 6 \times 25

A=210

Area is 210 Sq cm

c) Perimeter = Sum of all the sides

P = 7+4+7+4 ( as Opposite sides are equal in a parallelogram

P = 22

Perimeter is 22 yards

Area of a parallelogram = base \times height

A= 7 \times 3

A = 21

Area is 21 Sq Yards

3 0
3 years ago
Please help me!!!!!
umka21 [38]
It’s a because the total of x and y is 6.80 and the second equation is how much each are and the total being 7.

Brainliest?
5 0
3 years ago
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