a₁ = 4
n = 10
d = 3
a = a₁ + (n - 1)d
a₁₀ = 4 + (10 - 1)3
a₁₀ = 4 + (9)3
a₁₀ = 4 + 27
a₁₀ = 31
The 10th term would be 31 and the d variable will be replaced with the number 3.
Answer:
taste of your own medicine jk
Step-by-step explanation:
Set up both fractions as equal to each other then cross multiply to solve for x!
The picture will guide you through the process
Answer:
x=4
Step-by-step explanation:
1 Add 11 to both sides.
2x=7+12x=7+1
2 Simplify 7+17+1 to 88.
2x=82x=8
3 Divide both sides by 22.
x=\frac{8}{2}x=
2
8
4 Simplify \frac{8}{2}
2
8
to 44.
x=4x=4
cheek:
1 Let x=4x=4.
2\times 4-1=72×4−1=7
2 Simplify 2\times 42×4 to 88.
8-1=78−1=7
3 Simplify 8-18−1 to 77.
7=7 7=7
(or -3)
Answer:
(a) Two x plus eight is greater than negative four
(b) x > -6; number line would be an open circle at -6 and the line pointing in the positive direction to be shaded
Step-by-step explanation:
(a)
Note first that the inequality sign ">" means "greater than", so 2x + 8 > -4 in written language is:
<em>Two x plus eight </em><em>is greater than</em><em> negative four</em>
<em />
(b)
We solve this just like how we'd solve it if it were 2x + 8 = -4: isolate the variable first.
Subtract 8 from both sides:
2x + 8 - 8 > -4 - 8
2x > -12
Divide by 2:
x > -12/2
x > -6
So, the solution set is all numbers greater than -6.
Drawn on a number line, we would first place an <em>open circle</em> at -6 (because we are using > rather than ≥, which would include the -6 in the solution set). Then, because our solution set includes all numbers greater than -6, we shade in the part of the line that points in the positive direction, so it should include numbers like -5, -4, -3, -2, -1, 0, 1, 2, ... and so on.
