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stira [4]
3 years ago
8

What is the answer for this equation?

Mathematics
1 answer:
puteri [66]3 years ago
6 0
Is there a picture to go along with it? Because it's asking for the measure of ABD which is a triangle or a ray or something
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Find the slope of the line graphed​
jek_recluse [69]

Answer:

THERES NO PIC I CANT SEE

Step-by-step explanation:

6 0
3 years ago
The mean weight of an adult is 69 kilograms with a variance of 121. If 31 adults are randomly selected, what is the probability
amid [387]

Answer:

0.2236 = 22.36% probability that the sample mean would be greater than 70.5 kilograms.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Also, important to remember that the standard deviation is the square root of the variance.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 69, \sigma = \sqrt{121} = 11, n = 31, s = \frac{11}{\sqrt{31}} = 1.97565

What is the probability that the sample mean would be greater than 70.5 kilograms?

This is 1 subtracted by the pvalue of Z when X = 70.5. So

Z = \frac{X - \mu}{\sigma}

By the Central limit theorem

Z = \frac{X - \mu}{s}

Z = \frac{70.5 - 69}{1.97565}

Z = 0.76

Z = 0.76 has a pvalue of 0.7764

1 - 0.7764 = 0.2236

0.2236 = 22.36% probability that the sample mean would be greater than 70.5 kilograms.

8 0
3 years ago
Due today, Help fast, I will mark brainliest<br><br><br>I need help with everything!! :(<br><br>​
GuDViN [60]

Answer:

Anupama wants to purchase a curtain of window for her study room, she measures its length as 14 m, breadth as 3m, how much cloth will she purchase?Geometry is, with arithmetic, one of the oldest branches of mathematics. It is concerned with properties of space that are related with distance, shape, size, and relative position of figures. A mathematician who works in the field of geometry is called a geometer. Wikipedia

4 0
2 years ago
Can you simplify 61/35
saw5 [17]
No. 61 is an odd number not divisible
8 0
3 years ago
Read 2 more answers
The volume of a shampoo filled into a container is uniformly distributed between 370 and 385 milliliters. (a) What are the mean
Olenka [21]

Answer:

(a) mean = 377.5ml. standard deviation = 4.33

(b) 0.333

(c) 384.25 ml

Step-by-step explanation:

(a)The mean:

\mu = \frac{385 + 370}{2} = 377.5 ml

The standard deviation:

\sigma = \frac{385 - 370}{\sqrt{12}} = 4.33

(b)

P(x < 375) = \frac{375 - 370}{385 - 370} = \frac{1}{3} \approx 0.333

(c)P(x > m) = 0.95

\frac{m - 370}{385 - 370} = 0.95

m - 370 = 14.25

m = 384.25ml

So the volumn of shampoo should be 384.25ml to exceed 95% of containers.

7 0
3 years ago
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