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3 years ago

Please ✨help✨ I need this as soon as possible

Mathematics

1 answer:

attashe74 [19]3 years ago

8 0

Yes they form a proportion the rate of change is 27.5
4*27.5=110
10*27.5=275
18*27.5=495
30*27.5=825

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How can you subtract mixed numbers when the fractions in the first mixed number is less than the fraction in the second mixed nu

VARVARA [1.3K]

Answer:

To subtract mixed numbers, subtract the whole number parts of the mixed numbers and then subtract the fraction parts in the mixed numbers. Finally, combine the whole number answer and the fraction answer to express the answer as a mixed number. Subtract. Simplify the answer and write as a mixed number.

Step-by-step explanation:

5 0

4 years ago

A pair of shorts are £15 in a 40%. What was the non-sale price

lana66690 [7]

Answer:

£10.71

Step-by-step explanation:

Given the original price including discount od shorts = £15

Percent discount = 40%

Original price = x

Using the expression to calculate x

x + (40%of x) = 15

x +0.4x = 15

1.4x = 15

x = 15/1.4

x = £10.71

Hence the non sale price is £10.71

4 0

3 years ago

Using distributive property

Hoochie [10]

Answer:

Step-by-step: Step 1: Add -19x to both sides

48x-6y+3+-19x=19x+15y+-19x

29x-6y+3=15y

Step 2: Add 6y to both sides

29x-6y+3+6y=15y+6y

29x+3=21y

Step 3: Add -3 to both sides

29x+3+-3=21y+-3

29x=21y-3

Step 4: Divide both sides by 29

29x/29=21y-3/29

x=21/29y+ -3/29

3 0

3 years ago

Suppose that minor errors occur on a computer in a space station, which will require re-calculation. Assume the occurrence of er

Molodets [167]

Answer:

$P(X = 0) = 0.6065$

$P(x < 25 ) = 1.18 *10^{-33}$

$P(x \le 5 ) = 0.9994$

Step-by-step explanation:

From the question we are told that

The rate is $\lambda = \frac{1}{2}\ hr^{-1}$ = 0.5 / hr

Generally Poisson distribution formula is mathematically represented as

$P(X = x) = \frac{(\lambda t) ^x e^{-\lambda t }}{x!}$

Generally the probability that no error occurred during a day is mathematically represented as

Here t = 1 hour according to question a

$P(X = x) = \frac{\lambda^x e^{-\lambda}}{x!}$

Hence

$[tex]P(X = 0) = \frac{\frac{1}{2} ^0 e^{-\frac{1}{2}}}{0!}$

=> $P(X = 0) = 0.6065$

Generally the probability that a critical error occurs since the start of a day is mathematically represented as

Here t = 1 hour according to question a

$P(X = x) = \frac{\lambda^x e^{-\lambda}}{x!}$

Hence

$P(x \ge 25 ) = 1 - P(x < 25 )$

Here

$P(x < 25 ) = \sum_{x=0}^{24} \frac{e^{-\lambda} * \lambda^{x}}{x!}$

=> $P(x < 25 ) = \frac{e^{-0.5} *0.5^{0}}{0!} + \cdots + \frac{e^{-0.5} *0.5^{24}}{24!}$

$P(x < 25 ) = 0.6065 + \cdots + \frac{e^{-0.5} *0.5^{24}}{6.204484 * 10^{23}}$

$P(x < 25 ) = 0.6065 + \cdots + 6.0*10^{-32}$

$P(x < 25 ) = 1.18 *10^{-33}$

Considering question c

Here t = 2

Gnerally given that the system just started up and an error occurred the probability the next reset will occur within 2 hours

$P(x \le 5 ) = \sum_{n=0}^{5} \frac{(\lambda t) ^x e^{-\lambda t }}{x!}$

=> $P(x \le 5 ) = \frac{(0.5 * 2) ^ 0 e^{- 0.5 * 2 }}{0!} + \cdots + \frac{(0.5 * 2) ^ 5 e^{- 0.5 * 2 }}{5!}$

=> $P(x \le 5 ) = \frac{1* 2.7183 }{1 } + \cdots + \frac{1 *2.7183 }{120}$

=> $P(x \le 5 ) = 2.7183 + \cdots + 0.0226525$

$P(x \le 5 ) = 0.9994$

8 0

3 years ago

Evaluate and show all steps.<br> (4/7+8) * (3-(-4))

Akimi4 [234]

Yo sup??

we should know that negative*negative=positive

(4+7*8/7)*(3+4)

=60/7*7

=60

Hope this helps

5 0

4 years ago