You can do 8 piles because 8×8=64. So 8 groups with 8 candies in each group. :)
X = y + 1...so sub in y + 1 for x in the other equation
4x + 3y = -31
4(y + 1) + 3y = -31...distribute thru the parenthesis
4y + 4 + 3y = -31...subtract 4 from both sides
4y + 3y = -31 - 4....combine like terms
7y = - 35...divide both sides by 7
y = -35/7
y = - 5
now sub -5 in for y in either of the original equations to find x
x = y + 1
x = -5 + 1
x = -4
solution is (-4,-5)
Answer:
- (x + 3)(x - 3)(x^2 -3x + 9)(x^2 + 3x + 9)
Step-by-step explanation:
<u><em>Use of formulas:</em></u>
- <em>a^2 - b^2 = (a + b)(a -b)</em>
- <em>a^3 + b^3 = (a + b)(a^2 - ab + b^2)</em>
- <em>a^3 - b^3 = (a - b)(a^2 + ab + b^2)</em>
<u>Given the expression: </u>
<u>Factoring 729</u>
<u>Factoring the expression </u>
- x^6 - 3^6 =
- (x^3)^2 - (3^3)^2 =
- (x^3 + 3^3)(x^3 - 3^3) =
- (x + 3)(x^2 -3x + 9)(x - 3)(x^2 + 3x + 9) =
- (x + 3)(x - 3)(x^2 -3x + 9)(x^2 + 3x + 9)
This question is about compound interest, but since the interest is such a small number you can use what you know about simple interest to eliminate some answers.
You can immediately eliminate choice A as a clunker, since it is less than the original amount in the account.
Consider what the amount of interest would be if you make the rate much larger than the original rate, say 10%, or 0.1:
$6,500 × 0.1 = $650
If this amount were added to the original amount each year for two years, the total would be:
$6,500 + $650 + $650 = $6,500 + $1,300 = $7,800
This is an over-estimate for the information given, and since choices C and D are even greater than this over-estimate, they can be eliminated. That means choice B is the correct answer.
It's 35<21-n because 35 is less that 21 and an unknown number