Answer:
The probability of selecting a solid black marbles both times;
P = 9/100
Attached is the completed question;
Step-by-step explanation:
Number of solid black marbles = 3
Total number of marbles = 10
The probability of selecting a solid black marble;
P1 = 3/10
With the assumption that the marbles are replaced before next selection.
The probability of selecting a solid black marbles both times;
P = P1 × P1 = 3/10 × 3/10 = 9/100
P = 9/100
Answer:
(4, -3)
Step-by-step explanation:
Answer:
see explanation
Step-by-step explanation:
(a)
Note the squared value in column 3 which is the square of 1 more than the row number, that is
row 2 → (2 + 1)² →3²
row 3 → (3 + 1)² → 4²
Find the square root of 676 = 26 → (25 + 1)² = 26²
Hence the row number is 25
(b)
The pattern in column 1 is [ row number × (row number + 2 ) + 1 ]
row number is n then n(n + 2) + 1 = n² + 2n + 1
Answer:
240000000 times bigger.
If we solve 3x10^8 we get 300000000
Then if we solve for 6x10^7 we get 60000000
Subtract those two using long subtraction to evaluate and we get 240000000
Answer:
It's 19.
Step-by-step explanation:
Use order of operations (PEMDAS):
2^2[4+(3-6)^2]-13
Parentheses first:
= 2^2[4 + (-2)^2] - 13
= 2^2 ( 4 + 4) - 13
= 2^2 * 8 - 13
Now work out the exponent:
= 4*8 - 13
Now the multiplication:
= 32 - 13
= 19.