The value of integration of y=16-
from x=-1 to x=1 is 94/3.
Given the equation y=16- and the limit of the integral be x=-1,x=1.
We are required to find the value of integration of y=16- from x=-1 to x=1.
Equation is relationship between two or more variables that are expressed in equal to form.Equation of two variables look like ax+by=c.It may be linear equation, quadratic equation, or many more depending on the power of variable.
Integration is basically opposite of differentiation.
y=16-
Find the integration of 16-.
=16x-
Now find the value of integration from x=-1 to x=1.
=16(1)-
-16(-1)-
=16(1)-1/3+16-1/3
=32-2/3
=(96-2)/3
=94/3
Hence the value of integration of y=16- from x=-1 to x=1 is 94/3.
Learn more about integration at brainly.com/question/27419605
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Answer:
B
Step-by-step explanation:
The figure is a trapezium with area (A) calculated as
A = 
h (a + b)
where h is the perpendicular height and a, b the parallel bases
Here h = 8, a = 10 and b = 6, thus
A = × 8 × (10 + 6) = 4 × 16 = 64 cm² → B
Tge answer is 598,802.395 because if you put it into tge calculator you should get this answer
12x-3-3x=5-(x-8)
9x-3=5-(x-8)
9x-3=5-x+ 8
9x-3=13-x
9x=16- x
10x=16
X= 8/5
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