<h2>Answer:</h2><h2>1 9/16 or 1.5625</h2><h2></h2><h2>Hope this helps!!</h2>
Answer:
Subtract 18 from both sides
Step-by-step explanation:
509 people.


you can't have 0.094 of someone so we round the answer off the 509.
Answer:
a) How many loops does this pattern exhibit = 3Loops
b) What is the fundamental frequency of vibration of the wire = 50Hz
c) how many loops arepresent in the new pattern = 1 Loop
Step-by-step explanation:
The concept of general wave equation is applied and then compared to the equation given in the question to determine the amplitude A, and angular frequency w as shown in the attached file.
<span>Give that </span>t<span>he frequency of G5 is 783.99 Hz.
To find the frequency of the note that is a perfect fifth above G5, we recall that </span>the frequencies of notes that are a 'perfect'
fifth apart are in the ratio of 1.5
i.e. <span>the frequency of the note that is a perfect fifth above G5 divided by </span><span>t<span>he frequency of G5 equal 1.5
Let the </span></span><span><span>frequency of the note that is a perfect fifth above G5 be F, then
F / </span>783.99 = 1.5
F = 1.5 x 783.99 = 1175.99
Therefore, </span>the <span>frequency of the note that is a perfect fifth above G5</span> is 1175.99 Hz