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3 years ago

What is equation of the line that passes through the point (-3,8) and has an undefined slope

Mathematics

1 answer:

aniked [119]3 years ago

8 0

The equation of line that passes through point (-3, 8) and has an undefined slope is x = -3

Solution:

Given that we have to find the equation of line that passes through point (-3, 8) and has an undefined slope

Since the line has an undefined slope. This informs us that it is a vertical line parallel to the y-axis and passing through all points in the plane with the same x-coordinate.

If the slope of the line is undefined, then, by definition the line is a vertical line.

For a vertical line, the value of x is the same for each and every value of y

Given point is (x, y) = (-3 , 8)

Because the value of x in the point provided in the problem is -3, we get

Equation of line is : x = -3

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alexira [117]

Answer:

50/7.

Simplified to 7.14.

Step-by-step explanation:

Combine like terms, 5x and 9x.

5x+9x=14x

14x = 100

14x / 14 = 100 / 14

x = 50/7 or 7.14

Hope this helps!

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luda_lava [24]

La altura del triangulo está dada por el polinomio:

p(x) = a + 4

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A = B*H/2

En este caso, sabemos que la base es B = (4*a^2 + 6)

Y el area es A = 2a^3 + 8a^2 +3a +12

Entoces la altura será un polinomio tal que:

P(a)*(4*a^2 + 6)/2 = 2a^3 + 8a^2 +3a +12

P(a)*(4*a^2 + 6) = 2*(2a^3 + 8a^2 +3a +12) = 4a^3 + 16a^2 + 6a + 24

Podemos ver que p(a) va a ser un polinomio de grado 1, entonces:

p(a) = (c*a + b)

Reemplazando eso:

(c*a + b)*(4*a^2 + 6) = 4a^3 + 16a^2 + 6a + 24

Expandiendo:

(4c)*a^3 + (6c)*a + (4b)*a^2 + 6*b = 4a^3 + 16a^2 + 6a + 24

Comparando terminos del mismo exponente, podemos ver que:

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b = 16/4 = 4

c = 4/4 = 1

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p(x) = a + 4

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https://brainly.lat/tarea/17903571

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