Answer:
A. 121 ⇒ III. 11
B. 64 ⇒ II. 4 and IV. 8
C. 27 ⇒ I. 3
D. 125 ⇒ V. 5
E. 16 ⇒ II. 4
Step-by-step explanation:
Let us find the correct answer
∵ 121 = 11 × 11
∴ The square root 121 is 11
∴ A. 121 ⇒ III. 11
∵ 64 = 8 × 8
∴ The square root of 64 is 8
∵ 64 = 4 × 4 × 4
∴ The cube root of 64 is 4
∴ B. 64 ⇒ II. 4 and IV. 8
∵ 27 = 3 × 3 × 3
∴ The cube root of 27 is 3
∴ C. 27 ⇒ I. 3
∵ 125 = 5 × 5 × 5
∴ The cube root of 125 is 5
∴ D. 125 ⇒ V. 5
∵ 16 = 4 × 4
∴ The square root of 16 is 4
∴ E. 16 ⇒ II. 4
Answer:
x=y
Step-by-step explanation:
Answer: The equation for the line of reflection will be x = y.
I think it might be B I’m so sorry if it’s not
Answer:
![y=[1]cos([\frac{2\pi }{3}]x)](https://tex.z-dn.net/?f=y%3D%5B1%5Dcos%28%5B%5Cfrac%7B2%5Cpi%20%7D%7B3%7D%5Dx%29)
Step-by-step explanation:
Looking at the graph, we can see the domain to be from (0 , 2π).
Now we have to find one period that corresponds to cos(x).
The half-period of cos(x) for this graph appears to be pi/3 and adding another pi/3 gets us 2pi/3 to be our cosine period.
b = 2pi/3
a is the same range as cos(x). Range: (0,0)
y = [a] * cos ([b]*x)
y = [1] * cos([2pi/3]x)
Answer:
The answer is x = 2
Step-by-step explanation:
6x - 7x + 2 = 0
-x + 2 = 0
-x = -2
x = 2