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Gekata [30.6K]
3 years ago
14

HW please help it’s due today

Mathematics
1 answer:
djyliett [7]3 years ago
3 0

Answer:

C

Step-by-step explanation:

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Find the real solutions of the equation. (2x-6)^2 + 4(2x -6) +3 = 0
miskamm [114]

Answer:

(

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(

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Simplify the left side.

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(

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Use the quadratic formula to find the solutions.

−

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Substitute the values  

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The final answer is the combination of both solutions.

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7 0
3 years ago
Can someone please help me and explain to me how to do this geometry problem please? thank you!! ❤
Dennis_Churaev [7]
Measures of angles 2, 3, 4, added equal 180

3 0
4 years ago
InWrite the equation of the line that passes through (7, - 4) and (- 1, 2) slope- intercept form.
blondinia [14]

Answer:

General Equation of a Line

General Equation \\(y - y_{1} )= m (x-x_{1}) \\Slope=m= \frac{x_{2}-x_{1} }{y_{2}-y_{1} } \\\\Given:\\p_{1}=(7,-4)\\p_{2}=(-1,2)\\Solution:\\m=(\frac{-1-7}{2-(-4)}) =\frac{-8}{6}\\y-(-4) = (\frac{-8}{6} )(x-7)\\y+4=\frac{-8x}{6} + 56\\y=\frac{-8x}{6} + 52 \\\\The\\  equation \\ is \\ y=\frac{-8x}{6} + 52

Step-by-step explanation:

Find the slope first and then place the values on the general formula. The final step is to solve for y

5 0
3 years ago
Find the 9th term of the geometric sequence 5, -25, 125, ...
Mnenie [13.5K]

Answer:  1,953,125

This is one single value and it is just a bit under 2 million.

Or more accurately, it's a bit over 1.9 million.

===========================================================

Explanation:

  • a = 5 = first term
  • r = -5 = common ratio

Note that dividing any term by its previous term gets us the common ratio

  • r = term2/term1 = -25/5 = -5
  • r = term3/term2 = 125/(-5) = -5

The r value must stay the same the entire time, or else the sequence isn't geometric.

The nth term of any geometric sequence is a*(r)^(n-1). With the 'a' and 'r' values we found, we update that to 5(-5)^(n-1)

-----------------

To verify that is the correct nth term expression, plug in various values of n to compare it with the given sequence.

If we tried n = 2 for instance, then we find the 2nd term is

5(-5)^(n-1) = 5(-5)^(2-1) = -25

which matches what your teacher gave you. I'll let you verify the other terms.

-----------------

The last thing we need to do is plug in n = 9 and simplify

5(-5)^(n-1)

5(-5)^(9-1)

5(-5)^8

5(390625)

1,953,125  this is one single value (rather than 3 separate values)

4 0
3 years ago
Can someone please simplify the complex fraction?
dmitriy555 [2]
\bf \cfrac{\qquad \frac{x+3}{4x^2-16}\qquad }{\frac{2x^2+10x+12}{2x-4}}\implies \cfrac{\frac{x+3}{4(x^2-4)}}{\frac{\underline{2}(x^2+5x+6)}{\underline{2}(x-2)}}\implies \cfrac{\frac{x+3}{4(x^2-2^2)}}{\frac{x^2+5x+6}{x-2}}\implies \cfrac{\frac{x+3}{4(x-2)(x+2)}}{\frac{(x+3)(x+2)}{x-2}}

\bf \cfrac{\underline{x+3}}{4\underline{(x-2)}(x+2)}\cdot \cfrac{\underline{x-2}}{\underline{(x+3)}(x+2)}\implies \cfrac{1}{4(x+2)}\cdot \cfrac{1}{x+2}
\\\\\\
\cfrac{1}{4(x+2)(x+2)}\implies \cfrac{1}{4(x^2+4x+4)}\implies \cfrac{1}{4x^2+16x+16}
8 0
3 years ago
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