HW please help it’s due today

<img src="https://tex.z-dn.net/?f=10-%5Cfrac%7B3y-1%7D%7B2%7D%20%3D%5Cfrac%7B6y%2B3%7D%7B11%7D" id="TexFormula1" title="10-\frac

Ghella [55]

$10-\frac{3x-1}{2} =\frac{6x+3}{11}$

$10 = \frac{6x+3}{11} + \frac{3x-1}{2}$

$10 = (\frac{6x+3}{11} \times \frac{2}{2} ) + (\frac{3x-1}{2} \times \frac{11}{11} )$

$10 = ( \frac{2(6x + 3)}{22} ) + ( \frac{11(3x - 1)}{22} )$

$10 = \frac{12x + 6}{22} + \frac{33x - 11}{22}$

$10 = \frac{12x + 6 + 33x - 11}{22}$

$10 = \frac{(12 x + 33x) + (6 - 11)}{22}$

$10 = \frac{45x - 5}{22}$

$10 \times 22 = 45x - 5$

$220 = 45x - 5$

$220 + 5 = 45x$

$225 = 45x$

$\frac{225}{45} = x$

$\frac{45}{9} = x$

$5 = x$

7 0

2 years ago

The volume inside of a sphere is V=4πr33 where r is the radius of the sphere. Your group has been asked to rearrange the formula

Semmy [17]

Answer:

Therefore,

$r=\sqrt[3]{\frac{3V}{4\pi }}$

is the required r

Step-by-step explanation:

Given:

Volume of inside of the sphere is given as

$V=\frac{4}{3} \pi r^{3}$

where r is the radius of the sphere

To Find:

r =?

Solution:

We have

$V=\frac{4}{3} \pi r^{3}$ ......Given

$3\times V=4\pi r^{3} \\\\\therefore r^{3}=\frac{3V}{4\pi } \\\\\therefore r=\sqrt[3]{\frac{3V}{4\pi }} \textrm{which is the expression for r}$

Therefore,

$r=\sqrt[3]{\frac{3V}{4\pi }}$

is the required r

5 0

3 years ago

Which of the following expressions are equivalent to \dfrac{-10}{3}

andreyandreev [35.5K]

Answer:

B

Step-by-step explanation:

I don't know how to explain it, but I hope I got it right and that it helped you.

7 0

2 years ago

Read 2 more answers

1. How much work is done when a 65 newton force moves a block 5 meters?

Alik [6]

Answer:

i am not sure but i might know how to do it

Step-by-step explanation:

work is described as taking place when a force acts upon an object to cause a displacement. When a force acts to cause an object to be displaced, three quantities must be known in order to calculate the work. Those three quantities are force, displacement and the angle between the force and the displacement. The work is subsequently calculated as force•displacement•cosine(theta) where theta is the angle between the force and the displacement vectors. In this part of Lesson 1, the concepts and mathematics of work will be applied in order to analyze a variety of physical situations

8 0

3 years ago

Solve over the set of real numbers for the equation below x-2=√2x-1

Anon25 [30]

The set of real numbers for the equation x – 2 = √(2x – 1) will be 5.

<h3>What is the solution of the equation?</h3>

The solution of the equation means the value of the unknown or variable.

The equation is given below.

x – 2 = √(2x – 1)

Square on both side, then we have

(x – 2)² = 2x – 1

x² – 4x + 4 = 2x – 1

x² – 6x + 5 = 0

x² – 5x – x + 5 = 0

x(x – 5) – 1(x – 5) = 0

(x – 5)(x – 1) = 0

x = 1, 5

The set of real numbers for the equation x – 2 = √(2x – 1) will be 5.

More about the solution of the equation link is given below.

brainly.com/question/545403

#SPJ1

6 0

2 years ago