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Ilia_Sergeevich [38]
2 years ago
11

Ok I have to make multiple questions since the max amount of attachments is 5 but this is the first one.

Mathematics
1 answer:
Pie2 years ago
4 0

Answer:

All answers are down below!

Step-by-step explanation:

PAGE 1

22.) -10x - 2y = 20 (add 10x on both sides)

-2y = 10x + 20 (divide by -2 on both sides)

y = -5x - 10

Neither because perpendicular lines have opposite reciprocal and opposite sign. This equation only has opposite sign. It's not parallel because parallel lines have the same slope, and this equation doesn't.

23.) <1 = 138 b/c 180 -42

<2 = 42 b/c vertical to the angle measured 42

<3 = 138 b/c it's vertical to <1 and vertical angles have the same measure

<4 = 42 b/c it is an alternate interior angle to <2

<5 = 90 b/c vertical to <8

<6 = 48 b/c <4 + <5 + <6 = 180 and 42 + 90 + 48 = 180

<7 = 42 b/c it is vertical to <4 which also has a measure of 42

<8 = 90 b/c it is same side interior to <10 which has a measure of 90 degrees

<9 = 48 b/c <7 + <8 = 132 and 180 -132 = 48

<10 = 90 b/c it is a linear pair with the right angle and a right angle equals 90 degrees

PAGE 2

1.) PQ, QR, and NR

2.) ML, NP, and RQ

3.) KL, JM, JN, and KP

4.) corresponding angles

5.) alternate interior angles

6.) alternate exterior angles

7.) interior consecutive angles or same side interior angles

PAGE 3

9.) Q'(5, -4) R'(5, -2) S'(1, -3) because (x, y) ----> (-x, y)

10.) J'(3, 5) I'(1, 1) H'(3, 1) G'(4, 5) b/c (x,y) -----> (x, -y)

11.) E'(1, -4) F'(0, -2) G'(-3, -5) b/c (x,y) -----> (-x, y)

12.) J'(1, 2) K'(-1, -3) L'(4, -2) M'(3, 3) b/c (x,y) -----> (x, -y)

13.) Y'(-4, 1) X'(-3, 4) W'(-4, 5) b/c (x,y) -----> (y, x)

14.) J'(-3, 3) I'(5, 2) H'(-5, 1) G'(0, -1) b/c (x,y) ----> (-y, -x)

15.) H'(-2, 5) G'(2, 2) F'(3, 4) b/c (x,y) ------> (x, -y)

16.) U'(-2, -1) V'(0, 2) W'(-3, 4) b/c (x,y) ------> (y, x)

PAGE 4

17.) 3x - 43 = 80 (add 43 on both sides) --> 3x = 123 (divide by 3 on both sides) --> x = 41

18.) 8x - 6 = 90 (add 6 on both sides) ---> 8x = 96 (divide by 8 on both sides) --> x = 12

19.) 15x - 5 + 11x + 3 = 180 (collect like terms) --> 26x -2 = 180 (add 2 on both sides) ---> 26x = 182 (divide by 26 on both sides) --> x = 7

20.) To find slope use y2-y1/x2-x1

PLUG IN

2 - -5/ -1 - -5 =

7/4 since parallel lines have the same slope line b would also have a slope of 7/4.

21.) x + 3y = 2 (subtract x on both sides) ---> 3y = -x + 2 (divide by 3 on both sides)

y = -1/3x + 2/3. The lines are perpendicular because their slopes have opposite reciprocals and opposite signs.

PAGE 5

8.) 4x - 9 + 75 = 180 (collect like terms) --> 4x + 66 = 180 (subtract 66 on both sides) -----> 4x = 114 (divide by 4 on both sides) x = 28.5

9.) 7x + 2 = 65 (subtract 2 on both sides) --> 7x = 63 (divide by 7 on both sides) --> x =9

10.) Corresponding angles

11.) <7

12.) consecutive interior angles or same side interior angles

13.) <9

14.) Line C

15.) c || d

16.) a || b

Hope this helps you!!

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Answer:

B' = (-3,6)

Step-by-step explanation:

Given

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<em>Translation: 3 units left and 1 unit right</em>

Required

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When a function is shifted to the left, we have to subtract the unit from the x value of the function;

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<em />

When a function is shifted upward, we have to add the unit to the y value of the function;

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5 0
3 years ago
Which of the following is the standard form of the equation 5x2 - 20x = 15?
Sophie [7]
It is C. The first part is raised to the 2nd power. so it goes first since that is the highest. then the -20x because variables are understood to the power of 1, while normal numbers are understood to the power of 0. so the order is highest to lowest (2,1,0)
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Please help mee pleaseee
nalin [4]

Answer:

The exact answer in terms of radicals is x = 5*\sqrt[3]{25}

The approximate answer is x \approx 14.62009 (accurate to 5 decimal places)

===============================================

Work Shown:

Let y = \sqrt[5]{x^3}

So the equation reduces to  -7  = 8-3y

Let's solve for y

-7 = 8-3y

8-3y = -7

-3y = -7-8 ... subtract 8 from both sides

-3y = -15

y = -15/(-3) ... divide both sides by -3

y = 5

-----------

Since y = \sqrt[5]{x^3} and y = 5, this means we can equate the two expressions and solve for x

y = 5

\sqrt[5]{x^3} = 5

x^3 = 5^5 Raise both sides to the 5th power

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x = \sqrt[3]{3125} Apply cube root to both sides

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2 cakes - Theresa's and Joe's
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We know that 8/12ths of ONE cake were eaten and that Joe ate 2 of his pieces.
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Answer: Theresa ate 3 pieces of her cake

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